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Rudiy27
3 years ago
10

The following is a list of metals and alloys:

Engineering
1 answer:
viktelen [127]3 years ago
5 0

Answer:

A) Gray cast iron

B) Aluminum

C) Titanium alloy

D) Tool steel

E) Titanium alloy

F) magnesium

G) Tungsten

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For a bronze alloy, the stress at which plastic deformation begins is 266 MPa and the modulus of elasticity is105 GPa.
pentagon [3]

Answer:

88750 N

Explanation:

given data:

plastic deformation σy=266 MPa=266*10^6 N/m^2

cross-sectional area Ao=333 mm^2=333*10^-6 m^2

solution:

To determine the maximum load that can be applied without

plastic deformation (Fy).

Fy=σy*Ao

   =88750 N

7 0
3 years ago
Refers to the capability to keep moving forward on a specified grade.
Mademuasel [1]

Answer:

maneuverability

Explanation:

needless to say, I took the quiz

6 0
3 years ago
Which of the following describes an editor when writing a program?
Sergeu [11.5K]

Answer:

A place where code is written.

8 0
3 years ago
Read 2 more answers
java Your program class should be called RomanNumerals Write a program that asks the user to enter a number within the range of
Ann [662]

Answer:

// Scanner class is imported to allow program

// receive input

import java.util.Scanner;

// RomanNumerals class is defined

public class RomanNumerals {

   // main method that signify beginning of program execution

   public static void main(String args[]) {

       // Scanner object scan is created

       // it receive input via keyboard

       Scanner scan = new Scanner(System.in);

       // Prompt is display asking the user to enter number

       System.out.println("Enter your number: ");

       // the user input is stored at numberOfOrder

       int number = scan.nextInt();

     

           // switch statement which takes number as argument

           // the switch statement output the correct roman numeral

           // depending on user input

          switch(number){

           case 1:

               System.out.println("I");

               break;

           case 2:

               System.out.println("II");

               break;

           case 3:

               System.out.println("III");

               break;

           case 4:

               System.out.println("IV");

               break;

           case 5:

               System.out.println("V");

               break;

           case 6:

               System.out.println("VI");

               break;

           case 7:

               System.out.println("VII");

               break;

           case 8:

               System.out.println("VIII");

               break;

           case 9:

               System.out.println("IX");

               break;

           case 10:

               System.out.println("X");

               break;

           // this part is executed if user input is not between 1 to 10

           default:

               System.out.println("Error. Number must be between 1 - 10.");

     }

   }

}

Explanation:

The program is well commented. A sample image of program output is attached.

The switch statement takes the user input (number) as argument as it goes through each case block in the switch statement and match with the corresponding case to output the roman version of that number. If the number is greater 10 or less than 1; the default block is executed and it display an error message telling the user that number must be between 1 - 10.

6 0
3 years ago
Read 2 more answers
Problem 2 (a) A sinusoid with a frequency of 2Hz is applied to a sampler/zero-order hold combination. The sampling rate is 10Hz.
madreJ [45]

Answer & Explanation:

(a) Frequency of 2Hz is applied to a sampler/zero-order hold combination

The sampling rate is 10Hz

List of all the frequencies present in the output that are less than 50Hz.

Adding:

fs + fm = 10 + 2

= 12 Hz

2fs + fm = 2 * 10 + 2

= 22 Hz

3fs + fm = 3 * 10 + 2

= 32 Hz

4fs + fm = 4 * 10 + 2

= 42 Hz

Subtracting:

fs - fm = 10 - 2

= 8 Hz

2fs - fm = 2 * 10 - 2

= 18 Hz

3fs - fm = 3 * 10 - 2

= 28 Hz

4fs - fm = 4 * 10 - 2

= 38 Hz

5fs - fm = 5 * 10 - 2

= 48 Hz

(b) Frequency of 8Hz is applied to a sampler/zero-order hold combination

The sampling rate is 10Hz

List of all the frequencies present in the output that are less than 50Hz.

Adding:

fs + fm = 10 + 8

= 18 Hz

2fs + fm = 2 * 10 + 8

= 28 Hz

3fs + fm = 3 * 10 + 8

= 38 Hz

Subtracting:

fs - fm = 10 - 8

= 2 Hz

2fs - fm = 2 * 10 - 8

= 12 Hz

3fs - fm = 3 * 10 - 8

= 22 Hz

4fs - fm = 4 * 10 - 8

= 32 Hz

5fs - fm = 5 * 10 - 8

= 42 Hz

3 0
3 years ago
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