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bearhunter [10]
3 years ago
9

A. The temperature of a system is measured to be 75 °F. Express this temperature in °C, K, and R.

Engineering
1 answer:
Sauron [17]3 years ago
8 0

Answer:

Explanation:

a )

75°F = (75 - 32 ) x 5 / 9 = 35°C

35 + 273 = 308 K

75⁰F = 459.67 + 75 = 534.67° R

b )

\frac{F-32}{9} = \frac{C}{5}

F = C

\frac{F-32}{9} = \frac{F}{5}

5F - 160 =  9F

-4F = 160

F = - 40

Rankin = - 40 + 459.67 = 419.67

kelvin = -40 + 273 = 233K

c )

\frac{F-32}{9} = \frac{C}{5}

F = 2C

\frac{2C-32}{9} = \frac{C}{5}

10 C - 160 = 9C

C = 160°C

F = 320°F

R = 320 + 459.67 = 779.67°R

K = 273 + 160 = 433 K .

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I believe my house is manufactured
3 0
3 years ago
A heated long cylindrical rod is placed in a cross flow of air at 20°C (1 atm) with velocity of 10 m/s. The rod has a diameter o
postnew [5]

Answer:

Ts = 413.66 K

Explanation:

given data

temperature = 20°C

velocity = 10 m/s

diameter = 5 mm

surface emissivity = 0.95

surrounding temperature = 20°C

heat flux dissipated = 17000 W/m²

to find out

surface temperature

solution

we know that here properties of air at 70°C

k = 0.02881 W/m.K

v = 1.995 ×10^{-5} m²/s

Pr = 0.7177

we find here reynolds no for air flow that is

Re = \frac{\rho V D }{\mu } = \frac{VD}{v}    

Re = \frac{10*0.005}{1.99*10^{-5}}

Re = 2506

now we use churchill and bernstein relation for nusselt no

Nu = \frac{hD}{k} = 0.3 + \frac{0.62 Re6{0.5}Pr^{0.33}}{[1+(0.4/Pr)^{2/3}]^{1/4}} [1+ (\frac{2506}{282000})^{5/8}]^{4/5}

h = \frac{0.02881}{0.005}0.3 + \frac{0.62*2506{0.5}0.7177^{0.33}}{[1+(0.4/0.7177)^{2/3}]^{1/4}} [1+ (\frac{2506}{282000})^{5/8}]^{4/5}

h = 148.3 W/m².K

so

q conv = h∈(Ts- T∞ )

17000 = 148.3 ( 0.95) ( Ts - (20 + 273 ))

Ts = 413.66 K

5 0
4 years ago
A resource has value, and people are willing to pay for it most likely because the resource is
Galina-37 [17]

Answer:

abundant

Explanation:

6 0
3 years ago
Read 2 more answers
Find the phasor form of:
mixer [17]

Answer:

I=24.598\angle 50.377

Explanation:

A tension or current expressed in cosine form and with a positive sign can be converted directly into a phasor. This is done by indicating the tension and the offset angle:

Acos(10\omega t +\phi)=A\angle \phi

So:

i(t)=10cos(10t+63)+15cos(10t-42)=10\angle 63 + 15\angle42=I

You can sum the phasors simply using a calculator, however, let's do it manually:

Let's find the rectangular form of each phasor using the next formulas:

A=\sqrt{a^2+b^2} \\\phi=arctan(\frac{b}{a})

For 10\angle 63

63=arctan(\frac{b}{a} )\\\\tan(63)=\frac{b}{a} \\\\b=a*tan(63)

10=\sqrt{a^2+(a*tan(63))^2} \\\\10^2=a^2+a^2*(tan(63))^2\\\\Solving\hspace{3}for\hspace{3}a\\\\a=\sqrt{\frac{100}{1+tan(63)^2} } =4.539904997\\\\and\hspace{3}b\\b=\sqrt{100-a^2} =8.910065242

So:

Z_1=a+bj=4.539904997+8.910065242j

For 15\angle 42

42=arctan(\frac{b_2}{a_2} )\\\\tan(42)=\frac{b_2}{a_2} \\\\b_2=a_2*tan(42)

15=\sqrt{a_2^2+(a_2*tan(42))^2} \\\\15^2=a_2^2+a_2^2*(tan(42))^2\\\\Solving\hspace{3}for\hspace{3}a_2\\\\a_2=\sqrt{\frac{225}{1+tan(42)^2} } =11.14717238\\\\and\hspace{3}b_2\\\\b_2=\sqrt{225-a^2} =10.0369591

So:

Z_2=a_2+b_2j=11.14717238+10.0369591j

Hence:

Z_T=Z_1+Z_2=(4.539904997+11.14717238)+(8.910065242+10.0369591)j\\Z_T=15.68707738+18.94702434j

Finally:

I=\sqrt{15.68707738^2+18.94702434^2} \angle arctan (\frac{18.94702434}{15.68707738} )=24.598\angle 50.377

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3 years ago
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tester [92]

Answer:

See explaination

Explanation:

In recent times and in the past, so many companies have been dealt with or bankrupted by disaster.

This disasters are in the form of floods, earthquake and tsunami. This has led to many companies across world to have faced problem. As Japan is particularly vulnerable to natural disaster because of its climate and topography let me take example of japan .The tsunami that struck Japan in March this year which has lead to a debt of worth nearly $8 billion due to failed businesses. A total of 341 firms in japan with a combined 6,376 employees has got affected by this disaster.

One of company that hit hard by these disaster is Toyota. Toyota is a Japanese multinational automotive manufacturer headquartered in Toyota, Aichi, Japan. Actually due to flood in thailand toyota has faced a big loss. As flood hit thailand the parts of vehicle which is produced in thailand has stopped . It leads to interruption in the supply chain of some Thailand made components.

This lead to suspension of production as thai made component was unavailable.It has been reported until the situation of thailand will be good toyota plants in Indiana, Kentucky and Ontario, Canada, will be shut down . And production rate at plant in North America will get slow down .This flood leads to a loss of 37500 vehicles .Due to this reason toyota was forced to open its plants in Southeast asian country just to enhance the production rate.Sales of vehicle has also got reduced in thailand . Hence toyota faced a total loss of 1.6 billion dollar.

In Nigeria, due to the insurgency of the Boko Haram, many companies have entirely stopped operations in some regions, this harsh realities leads to massive loss of revenue for such companies.

3 0
4 years ago
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