Question

A cylindrical specimen of brass that has a diameter of 20 mm, a tensile modulus of 110 GPa, and a Poisson’s ratio of 0.35 is pulled in tension with force of 40,000 N. If the deformation is totally elastic, what is the strain experienced by the specimen?

Answer 1

Answer:

0.00116

Explanation:

Tensile modulus, $E=\frac {Stress}{Strain}$

Making strain the subject then

$Strain=\frac {Stress}{E}$

Since $stress=\frac {F}{A}$ then

$Strain=\frac {F}{AE}=\frac {40000}{\pi 0.01^{2}\times 110\times 10^{9}}=0.00115749\approx 0.00116$