<span>The more electronegative atom is reduced.</span>
8305 grams of HNO3 would be needed to prepare 5.5L of a solution. Details on how to calculate mass is found below.
<h3>How to calculate mass?</h3>
The mass of a substance in a solution can be calculated using the following formula:
Density = mass ÷ volume
According to this question, 5.5L of a HNO3 solution is given.
Density of HNO3 is 1.51 g/cm³
Volume of HNO3 = 5500mL
1.51 = mass/5500
mass = 8305g
Therefore, 8305 grams of HNO3 would be needed to prepare 5.5L of a solution.
Learn more about mass at: brainly.com/question/19694949
Answer:
%Yield ≈ 10.8% w/w
Explanation:
P₄ + 6Cl₂ => 4PCl₃
from equation rxn ratios 8 mol Cl₂ => 8(4/6) mole PCl₃ = 5.33 mole theoretically
Given Actual Yield = 0.5741 mole PCl₃;
%Yield = (Actual Yield / Theoretical Yield)100% = (0.5741/5.33)100% = 10.8%
It is simply not accurate due to many reasons such as environment, user, instrument as well as light which can easily change colours
