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Alina [70]
3 years ago
13

The force of attraction between 2 objects due to their masses is called what?

Physics
1 answer:
exis [7]3 years ago
4 0

Answer:

Gravitational force -an attractive force that exists between all objects with mass; an object with mass attracts another object with mass; the magnitude of the force is directly proportional to the masses of the two objects and inversely proportional to the square of the distance between the two objects.

pls give brainliest for the answer

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A 38kg child is at the top of a slide that is 2. 1m tall.
lana [24]

Answer:

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8 0
3 years ago
To measure the coefficient of kinetic friction by sliding a block down an inclined plane the block must be in equilibrium.
lozanna [386]

Answer:

a)

Explanation:

  • A block sliding down an inclined plane, is subject to two external forces along the slide.
  • One is the component of gravity (the weight) parallel to the incline.
  • If the inclined plane makes an angle θ with the horizontal, this component (projection of the downward gravity along the incline, can be written as follows:

        F_{gp} = m*g* sin \theta (1)

       (taking as positive the direction of the movement of the block)

  • The other force, is the friction force, that adopts any value needed to meet the Newton's 2nd Law.
  • When θ is so large, than the block moves downward along the incline, the friction force can be expressed as follows:

       F_{f} = \mu_{k} * N  (2)

  • The normal force, adopts the value needed to prevent any vertical movement through the surface of the incline:

       N = m*g* cos \theta (3)

  • In equilibrium, both forces, as defined in (1), (2) and (3) must be equal in magnitude, as follows:

        m*g* sin \theta =  \mu_{k} * m*g* cos \theta

  • As the block is moving, if the net force is 0, according to Newton's 2nd Law, the block must be moving at constant speed.
  • In this condition, the friction coefficient is the kinetic one (μk), which can be calculated as follows:

        \mu_{k}  = tg \theta

8 0
3 years ago
As an aid in working this problem, consult Interactive Solution 3.41. A soccer player kicks the ball toward a goal that is 20.0
alekssr [168]

Answer:

V=14.9 m/s

Explanation:

In order to solve this problem, we are going to use the formulas of parabolic motion.

The velocity X-component of the ball is given by:

Vx=V*cos(\alpha)\\Vx=15.7*cos(31^o)=13.5m/s

The motion on the X axis is a constant velocity motion so:

t=\frac{d}{Vx}\\t=\frac{20.0}{13.5}=1.48s

The whole trajectory of the ball takes 1.48 seconds

We know that:

Vy=Voy+(a)*t\\Vy=15.7*sin(31^o)+(-9.8)*(1.48)=-6.42m/s

Knowing the X and Y components of the velocity, we can calculate its magnitude by:

V=\sqrt{Vx^2+Vy^2} \\V=\sqrt{(13.5)^2+(-6.42)^2}=14.9m/s

6 0
4 years ago
0. A 5-kg block of ice is at a temperature of -27 °C. How much heat must be added to the ice to produce 5 kg of liquid water wit
stellarik [79]

Answer:

Q = 2687130 J

Explanation:

m = mass of block of ice = 5 kg

T_{i} = Initial temperature of ice block = - 27 °C

T_{f} = final temperature of water = 35 °C

c_{i} = specific heat of ice = 2108 J/(Kg °C)

L = Latent heat of fusion of ice = 334000 J/kg

c_{w} = specific heat of water = 4186 J/(Kg °C)

Heat added is given as

Q = m c_{i}(0 - T_{i})+ mL + m c_{w}(T_{f} - 0)

Q = (5) (2108)(0 - (-27))+ (5)(334000) + (5) (4186)(35 - 0)

Q = 2687130 J

8 0
3 years ago
The horizontal velocity of a projectile when it is in the air is ___.
irga5000 [103]

Answer:

its vi cos thita

Explanation:

3 0
3 years ago
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