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sweet [91]
2 years ago
13

A treasure map directs you to start at palm tree

Physics
1 answer:
masya89 [10]2 years ago
6 0

The direction of the 90° turns are the possible directions used for the calculations

The four distances and directions are;

  • <u>24.2 m, 65.6° West of North</u>
  • <u>29.7 m, 42.7° East of North</u>
  • <u>24.2 m, 65.6° East of North</u>
  • <u>29.7m, 47.7° West of North</u>

Reason:

Let point A represent the motion of the treasure hunter, we have:

Turning West then West;

Walking due north to location (0, 15)

Turn 90° West and walk 22.0 m to the location (-22, 15)

Turn 90° West again and walk 5.00 m. to the location (-22, 10)

The location of point A = (-22, 10)

Direction \ of \ point \ A = arctan \left(\dfrac{10}{-22} \right) \approx -24.4^{\circ}

Direction to North = 90° - 24.4° ≈ 65.6°

Distance = √((-22)² + 10²) ≈ 24.2

Therefore, we have;

  • 24.2 m, 65.6° West of North

Turning East then West:

Turn 90° East and walk 22.0 m to the location (22, 15)

Turn 90° West again and walk 5.00 m. to the location (22, 20)

The location of point A = (22, 20)

Direction \ of \ point \ A = arctan \left(\dfrac{20}{22} \right) \approx 42.7^{\circ}

Direction to North = 90° - 42.3° ≈ 47.7° East

Distance = √((-22)² + 20²) ≈ 29.7

Therefore, we have;

  • 29.7 m, 42.7° East of North

Turning East then East:

Turn 90° East and walk 22.0 m to the location (22, 15)

Turn 90° East again and walk 5.00 m. to the location (22, 10)

The location of point A = (22, 10)

Direction \ of \ point \ A = arctan \left(\dfrac{10}{22} \right) \approx 24.4^{\circ}

Direction to North = 90° - 24.4° ≈ 65.6° East

Distance = √((-22)² + 10²) ≈ 24.2

Therefore, we have;

  • 24.2 m, 65.6° East of North

Turning West then East:

Turn 90° West and walk 22.0 m to the location (-22, 15)

Turn 90° East and walk 5.00 m. to the location (-22, 20)

The location of point A = (-22, 20)

Direction \ of \ point \ A = arctan \left(\dfrac{20}{-22} \right) \approx -42.7^{\circ}

Direction to North = 90° - 42.7° ≈ 47.7° West

Distance = √((-22)² + 20²) ≈ 29.7

Therefore, we have;

  • 29.7m, 47.7° West of North

Learn more here:

brainly.com/question/11489059

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s344n2d4d5 [400]
I would say B but I’m not 100%
5 0
3 years ago
A computer is connected across a 110 V power supply. The computer dissipates 123 W of power in the form of electromagnetic radia
nexus9112 [7]

Answer:

81.3ohms

Explanation:

Resistance is known to provide opposition to the flow of electric current in an electric circuit.

Power dissipated by the computer is expressed as;

Power = current (I) × Voltage(V)

P = IV... (1)

Note that from ohms law, V = IR

I = V/R ... (2)

Substituting equation 2 into 1, we will have;

P = (V/R)×V

P = V²/R.. (3)

Given source voltage = 100V, Power dissipated = 123W

To get resistance R of the computer, we will substitute the given value into equation 3 to have

123 = 100²/R

R = 100²/123

R = 10,000/123

R = 81.3ohms

The resistance of the computer is 81.3ohms

3 0
3 years ago
Read 2 more answers
A small mailbag is released from a helicopter that is descending steadily at 3 m/s.
mario62 [17]

<u>Answer:</u>

a) Speed of mailbag after 3 seconds = 32.4 m/s

b) Package is 44.1 meter below helicopter

c) If the helicopter was rising steadily at 3.00 m/s

       Speed of mailbag after 3 seconds = 26.4 m/s

       Package is 44.1 meter below helicopter

<u>Explanation:</u>

a)  We have equation of motion, v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration and t is the time taken.

   Initial velocity = 3 m/s, acceleration = 9.8 m/s^2 and time = 3 seconds.

   v = 3+9.8*3 = 32.4 m/s

  Speed of mailbag after 3 seconds = 32.4 m/s

b) We have equation of motion , s= ut+\frac{1}{2} at^2, s is the displacement, u is the initial velocity, a is the acceleration and t is the time.

 Velocity of helicopter = 3 m/s, time taken = 3 seconds, acceleration = 0 m/s^2.

    s= 3*3+\frac{1}{2} *0*3^2\\ \\ s=9m

    Distance traveled by helicopter = 9 meter.

 Velocity of package = 3 m/s, time taken = 3 seconds, acceleration = 9.8 m/s^2.

  s= 3*3+\frac{1}{2} *9.8*3^2\\ \\ s= 53.1m

  Distance traveled by package  = 53.1 meter.

So package is (53.1-9)meter below helicopter = 44.1 m

c) Initial velocity = -3 m/s, acceleration = 9.8 m/s^2 and time = 3 seconds.

  v = -3+9.8*3 = 26.4 m/s

  Speed of mailbag after 3 seconds = 26.4 m/s

 Velocity of helicopter = -3 m/s, time taken = 3 seconds, acceleration = 0 m/s^2.

    s= -3*3+\frac{1}{2} *0*3^2\\ \\ s=-9m

    Distance traveled by helicopter = 9 meter.

 Velocity of package = -3 m/s, time taken = 3 seconds, acceleration = 9.8 m/s^2.

  s= -3*3+\frac{1}{2} *9.8*3^2\\ \\ s= 35.1m

  Distance traveled by package  = 35.1 meter.

So package is (35.1+9)meter below helicopter = 44.1 m

4 0
3 years ago
Two identical resistors connected in series have an equivalent resistance of 4 ohms. The same two resistors, when connected in p
irina1246 [14]

Answer:

1 ohm

Explanation:

since there are two identical resistors, one resistor will be

R = \frac{4}{2} =2ohm [ proven as in series R_{e} = 2 + 2 = 4ohm ]

to calculate the equivalent resistance when in parallel:

\frac{1}{R_{e} }  = \frac{1}{R_{1} } + \frac{1}{R_{2}}

so,

\frac{1}{R_{e} } = \frac{1}{2} + \frac{1}{2}

R_{e} = 1ohm

4 0
2 years ago
A car is traveling north at 17.7 m/s . After 6 it’s velocity is 141 in the same direction. Find the magnitude and direction of t
Furkat [3]

By equation of motion we have   v = u + at

Where u = Initial velocity, v = final velocity, t = time taken and a = acceleration

Here v = 141 m/s, u = 17.7 m/s and t = 6 s

On substitution we will get

        141 = 17.7+ 6a

       So, a = (141-17.7)/6 = 20. 55 m/s^{2}

       Aceeleration = 20. 55 m/s^{2} along north direction.


3 0
3 years ago
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