The direction of the 90° turns are the possible directions used for the calculations
The four distances and directions are;
- <u>24.2 m, 65.6° West of North</u>
- <u>29.7 m, 42.7° East of North</u>
- <u>24.2 m, 65.6° East of North</u>
- <u>29.7m, 47.7° West of North</u>
Reason:
Let point A represent the motion of the treasure hunter, we have:
Turning West then West;
Walking due north to location (0, 15)
Turn 90° West and walk 22.0 m to the location (-22, 15)
Turn 90° West again and walk 5.00 m. to the location (-22, 10)
The location of point A = (-22, 10)
Direction to North = 90° - 24.4° ≈ 65.6°
Distance = √((-22)² + 10²) ≈ 24.2
Therefore, we have;
- 24.2 m, 65.6° West of North
Turning East then West:
Turn 90° East and walk 22.0 m to the location (22, 15)
Turn 90° West again and walk 5.00 m. to the location (22, 20)
The location of point A = (22, 20)
Direction to North = 90° - 42.3° ≈ 47.7° East
Distance = √((-22)² + 20²) ≈ 29.7
Therefore, we have;
- 29.7 m, 42.7° East of North
Turning East then East:
Turn 90° East and walk 22.0 m to the location (22, 15)
Turn 90° East again and walk 5.00 m. to the location (22, 10)
The location of point A = (22, 10)
Direction to North = 90° - 24.4° ≈ 65.6° East
Distance = √((-22)² + 10²) ≈ 24.2
Therefore, we have;
- 24.2 m, 65.6° East of North
Turning West then East:
Turn 90° West and walk 22.0 m to the location (-22, 15)
Turn 90° East and walk 5.00 m. to the location (-22, 20)
The location of point A = (-22, 20)
![Direction \ of \ point \ A = arctan \left(\dfrac{20}{-22} \right) \approx -42.7^{\circ}](https://tex.z-dn.net/?f=Direction%20%5C%20of%20%5C%20point%20%5C%20A%20%3D%20arctan%20%5Cleft%28%5Cdfrac%7B20%7D%7B-22%7D%20%5Cright%29%20%5Capprox%20-42.7%5E%7B%5Ccirc%7D)
Direction to North = 90° - 42.7° ≈ 47.7° West
Distance = √((-22)² + 20²) ≈ 29.7
Therefore, we have;
- 29.7m, 47.7° West of North
Learn more here:
brainly.com/question/11489059