Answer:
the Jack speed is greater than the Nas speed
v₁ = 2.08 m / s > v2 = 1.85 m / s
Explanation:
For this exercise we can find the average speed of each of the boys, the average speed is defined as the displacement in the time interval
v = x / t
Jack.
It tells us that it travels x = 15 km in a time of t = 2 h
let's reduce the magnitudes to the SI system
x = 15 km (1000 m / 1 km) = 15 10³ m
t = 2 h (3600 s / 1 h) = 7200 s
let's calculate
v₁ = 15 10³/7200
v₁ = 2.08 m / s
Nas travels a distance of x = 10 km in a time of t = 1.5 h
x = 10 km = 10 10³ m
t = 1.5 h (3600s / 1h) = 5400 s
let's calculate the speed
v2 = 10 10³/5400
v2 = 1.85 m / s
From these results we can see that the Jack speed is greater than the Nas speed
Answer:
The answer for a classical particle is 0.00595
Explanation:
The equation of the wave function of a particle in a box in the second excited state equals:
ψ(x) = ((2/L)^1/2) * sin((3*pi*x)/L)
The probability is equal to:
P(x)dx = (|ψ(x)|^2)dx = ((2/L)^1/2) * sin((3*pi*x)/L) = (2/L) * sin^2((3*pi*x)/L) dx
for x = 0.166 nm
P(x)dx = (2/0.167) * sin^2((3*pi*0.166)/0.167) * 100 pm = 0.037x10^-3
for x = 0.028 nm
P(x)dx = (2/0.167) * sin^2((3*pi*0.028)/0.167) * 100 pm = 11x10^-3
for x = 0.067 nm
P(x)dx = (2/0.167) * sin^2((3*pi*0.067)/0.167) * 100 pm = 3.99x10^-3
therefore, the classical probability is equal to:
(1/L)dx = (1/0.167)*100 pm = 0.00595
Answer:
The branch of physical science that deals with the relations between heat and other forms of energy (such as mechanical, electrical, or chemical energy), and, by extension, of the relationships between all forms of energy.
Answer:
The other angle is 75⁰
Explanation:
Given;
velocity of the projectile, v = 10 m/s
range of the projectile, R = 5.1 m
angle of projection, 15⁰
The range of a projectile is given as;
To find another angle of projection to give the same range;
<u>Check: </u>
sin(2θ) = sin(2 x 75) = sin(150) = 0.5
sin(2θ) = sin(2 x 15) = sin(30) = 0.5
Answer:
3 m/s
Explanation:
Initial = Final
Mass * Velocity = Mass *Velocity
8000kg * 12m/s = (8000kg+ 24000kg) * (Final Velocity)
(96000 kgm/s) / (32000kg) = (Final Velocity)
Final Velocity = 3 m/s
