Answer:i am confused what is the question i will help tho
Step-by-step explanation:
Answer:
x=-2, y=1
Step-by-step explanation:
y=3x+7
y=-2x+3
Set the two equations equal to each other:
3x+7=-2x-3
Add 2x to both sides:
5x+7=-3
Subtract 7 from both sides:
5x=-10
Divide both sides by 5:
x=-2
Plug back into one of the original equations to find y:
y=3(-2)+7=-15+7=1
Hope this helps!
Let the slower train's velocity be x-21
Let the faster train's velocity be x
We know that the approach speed is the sum of both speeds, so x+x -21= 2x-21.
The approach rate is given by Distance/time = 471/3 = 157mpH
x+x-21=157
2x=157+21
2x=178
x=89mph
The slower train is travelling 89-21 = 68mph
The faster train is travelling 89mph.
Answer:
<h2>
√34sin(x + 0.33π)</h2>
Step-by-step explanation:
The general form of the equation acosx + bsinx = Rsin(x + e) where R is the resultant of the constants 'a' and 'b' and e is the angle between them.
R = √a²+b²
Given the function f(x) = 3 cos x + 5 sin x, comparing with the general equation;
a = 3, b = 5
R = √3²+5²
R = √9+25
R =√34
in radians;
3 cos x + 5 sin x = √34sin(x + 0.33π)
