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ehidna [41]
3 years ago
7

{System: I am having a bit of trouble calculating this. And I am reposting this sense I don’t think it’s fair to give only a lit

tle amount of points.. so I am making it higher! Please help me with this}

Mathematics
1 answer:
Darya [45]3 years ago
3 0

Total volume of light-blue paint:

\left(4+\dfrac38\right)+\left(6+\dfrac18\right)=10+\dfrac48=10+\dfrac12

Divide by \dfrac14 to find how many containers he can divided this total into:

\dfrac{10+\frac12}{\frac14}=4\left(10+\dfrac12\right)=40+\dfrac42=40+2=42

so the answer is B.

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AfilCa [17]
Answer:
The numbers are 9, 7, 4, 11
4 0
2 years ago
Find the distance between the two points in simplest radical form.<br> (3,9)and (0,2)
Aleks04 [339]

Answer:

7.62

Step-by-step explanation:

use distance formula

6 0
3 years ago
Given vectors u = (−1, 2, 3) and v = (3, 4, 2) in R 3 , consider the linear span: Span{u, v} := {αu + βv: α, β ∈ R}. Are the vec
julia-pushkina [17]

Answer:

(2,6,6) \not \in \text{Span}(u,v)

(-9,-2,5)\in \text{Span}(u,v)

Step-by-step explanation:

Let b=(b_1,b_2,b_3) \in \mathbb{R}^3. We have that b\in \text{Span}\{u,v\} if and only if we can find scalars \alpha,\beta \in \mathbb{R} such that \alpha u + \beta v = b. This can be translated to the following equations:

1. -\alpha + 3 \beta = b_1

2.2\alpha+4 \beta = b_2

3. 3 \alpha +2 \beta = b_3

Which is a system of 3 equations a 2 variables. We can take two of this equations, find the solutions for \alpha,\beta and check if the third equationd is fulfilled.

Case (2,6,6)

Using equations 1 and 2 we get

-\alpha + 3 \beta = 2

2\alpha+4 \beta = 6

whose unique solutions are \alpha =1 = \beta, but note that for this values, the third equation doesn't hold (3+2 = 5 \neq 6). So this vector is not in the generated space of u and v.

Case (-9,-2,5)

Using equations 1 and 2 we get

-\alpha + 3 \beta = -9

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whose unique solutions are \alpha=3, \beta=-2. Note that in this case, the third equation holds, since 3(3)+2(-2)=5. So this vector is in the generated space of u and v.

4 0
3 years ago
How does the word equidistant relate to the term perpendicular bisector?
disa [49]
A perpendicular bisector cuts a line segment directly in half. a property of perpendicular bisectors is that any point on the line of the bisector will be equidistant (the same distance from) both end points.

 Ex, If point X was 5 ft away from one endpoint, it would be 5 feet away from the other as well.
6 0
3 years ago
4 3/10 divided by 3/5
inysia [295]

Answer:

7.16

Step-by-step explanation:

5 0
3 years ago
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