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BlackZzzverrR [31]
3 years ago
7

Complete the pattern A12, B16, C20,​

Mathematics
2 answers:
valentina_108 [34]3 years ago
6 0
It’s go up by 4 , so 12 16 20 24 28 32 36












Ksju [112]3 years ago
5 0

Answer:it goes up by 4

Step-by-step explanation:

12 16 20 24 28 and so on

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Aida applied the distributive property to write the equivalent expressions below.
Julli [10]

Answer:

Option B is the answer.

Step-by-step explanation:

Aida applied the distributive property to write the equivalent expressions given as

15 + 21 = 3(4 + 8)

But Aida made a mistake.

Since to get the common factor of 15 and 21 she did not divide these number of 3 correctly.

In simple words by division of 3 in 15 and 21 we get 5 and 7 instead of 5 and 8.

Therefore, option B is the correct answer.

5 0
4 years ago
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Give three equivalent rates that describe the top speed of a tuna.​
Ksju [112]
27 miles per hour 29 miles per hour and 32 miles per hour
5 0
3 years ago
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To make 12 ounces of hot chocolate 3 tablespoons of cocoa are needed how many tablespoons of cocoa are needed to make 72 ounces
tiny-mole [99]

Answer:

you would need 18 tablespoons

Step-by-step explanation:

12--->72, so 3--->18

you are multiplying it by 6

6 0
3 years ago
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approximately what is the angle between two position vectors if their terminal points are (1,5) and (6,3)​
andre [41]

Answer:

The angle between them = 52.1°

Step-by-step explanation:

∵ The position vector of the first point is \left[\begin{array}{ccc}1\\5\end{array}\right]

∵ The position vector of the second point is \left[\begin{array}{ccc}6\\3\\\end{array}\right]

∵ The magnitude of the first = √(1²+5²) = √26

∵ The magnitude of the second = √(6²+3²) = √45

∵ The scalar product of them = (1 × 6) + (5 × 3) = 6 + 15 = 21

∵ cosФ = scalar product/(magnitude 1st × magnitude 2nd)

∴ cosФ = 21/(√26 × √45) = 0.61394

∴ Ф = 52.1°

7 0
4 years ago
Hell don’t understand homework If f(x)=<br> 5x-1
masya89 [10]

Answer:

(a)  -1

(b)  4

(c)  14

(d)  61

Step-by-step explanation:

A piecewise function is a function which has <u>different definitions</u> for <u>different intervals</u> of x.

Given:

f(x)=\begin{cases}5x-1 \quad \textsf{if }-5\leq x \leq 3\\x^3-3 \quad \textsf{if }\:\:\:\:\:\:3 < x \leq 4\end{cases}

f(x) has 2 definitions:

Definition 1

5x-1 when x is <u>more than or equal to -5</u> and <u>less than or equal to 3</u>.  This is a <u>linear function</u>.

Definition 2

x^2-3 when x is <u>more than 3</u> and <u>less than or equal to 4</u>.  This is a <u>cubic function</u>.

<u>Part (a)</u>

We have to find f(0), so when x = 0.

x = 0 satisfies the condition -5 ≤ x ≤ 3 so the corresponding function is

f(x)=5x-1

Substitute x = 0 in this definition:

\implies f(0)=5(0)-1=-1

<u>Part (b)</u>

We have to find f(1), so when x = 1.

x = 1 satisfies the condition -5 ≤ x ≤ 3 so the corresponding function is

f(x)=5x-1

Substitute x = 1 in this definition:

\implies f(0)=5(1)-1=4

<u>Part (c)</u>

We have to find f(3), so when x = 3.

x = 3 satisfies the condition -5 ≤ x ≤ 3 so the corresponding function is

f(x)=5x-1

Substitute x = 3 in this definition:

\implies f(0)=5(3)-1=14

<u>Part (d)</u>

We have to find f(4), so when x = 4.

x = 4 satisfies the condition 3 < x ≤ 4 so the corresponding function is

f(x)=x^3-3

Substitute x = 4 in this definition:

\implies f(4)=(4)^3-3=61

4 0
2 years ago
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