Find two triangles with the given angle measure and side lengths. Round side lengths to the nearest tenth and angle measures to
the nearest degree.
A = 61°, a = 14, b = 15
2 answers:
Answer:
its A
Step-by-step explanation:
b^2 = 6^2 + 11^2 - 2*6*11cos 109 = 199.97
b = 14.1 to nearest tenth.
now use sine rule to find the value of < A
14.14 / sin 109 = 6 / sin A
<A = 24 degrees
<C = 180 - 24 - 109 = 47 degrees
<3
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