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2 years ago

HELP RN RN RN RN PLEASE ASAP

1 answer:

3 0

I think the answer is A) stratified random sampling! Stratified random sampling is when sunsets of individuals are created based on similar criteria, which sounds the closest to the problem because stratified can split a group and does not have to be fully equal.
Non random sampling doesn’t fit because it’s clearly stated that it’s random.
Systematic random sampling is based on intervals in a group.
The next closest answer would be simple random, which is when a subset of individuals are chosen from a larger group with all having the same probability.

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3 years ago

What is the greatest common factor of 12 and 18?<br> A. 2 B. 6 C. 4 D. 12

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Answer:

B. 6

Step-by-step explanation:

D. 12 cant be multiplied to get 18

C. 4 cant be multiplied to get 18

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2 years ago

Read 2 more answers

For the hypothesis test H0: μ = 10 against H1: μ >10 and variance known, calculate the Pvalue for each of the following test

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Answer:

a) $p_v =P(Z>2.05)=1-P(z$

b) $p_v =P(Z>-1.84)=1-P(z$

c) $p_v =P(Z>0.4)=1-P(z$

Step-by-step explanation:

Some previous concepts

The p-value is the probability of obtaining the observed results of a test, assuming that the null hypothesis is correct.

A z-test for one mean "is a hypothesis test that attempts to make a claim about the population mean(μ)".

The null hypothesis attempts "to show that no variation exists between variables or that a single variable is no different than its mean"

The alternative hypothesis "is the hypothesis used in hypothesis testing that is contrary to the null hypothesis"

Hypothesis

Null hypothesis: $\mu=10$

Alternative hypothesis: $\mu >10$

If the random variable is distributed like this: $X \sim N(\mu,\sigma)$

We assume that the variance is known so the correct test to apply here is the z test to compare means, the statistic is given by the following formula:

$z_o=\frac{\bar X -\mu}{\sigma}$

Since we have the values for the statistic already calculated we can calculate the p value using the following formulas:

Part a

$p_v =P(Z>2.05)=1-P(z$

And in order to find the answer using excel we can use the following code:

"=1-NORM.DIST(2.05,0,1,TRUE)"

Part b

$p_v =P(Z>-1.84)=1-P(z$

And in order to find the answer using excel we can use the following code:

"=1-NORM.DIST(-1.84,0,1,TRUE)"

Part c

$p_v =P(Z>0.4)=1-P(z$

And in order to find the answer using excel we can use the following code:

"=1-NORM.DIST(0.4,0,1,TRUE)"

Conclusions

If we use a reference value for the significance, let's say $\alpha=0.05$ . For part a the $p_v$ so then we can reject the null hypothesis at this significance level.