General 'rule' - "like dissolves like". The solubility
of a solute in a solvent (that is, the extent of the mixing of the
solute and solvent species) depends on a balance between the natural
tendency for the solute and solvent species to mix and the tendency for a
system to have the lowest energy possible.
Hope this helps :p
Answer:
k = 1.3 x 10⁻³ s⁻¹
Explanation:
For a first order reaction the integrated rate law is
Ln [A]t/[A]₀ = - kt
where [A] are the concentrations of acetaldehyde in this case, t is the time and k is the rate constant.
We are given the half life for the concentration of acetaldehyde to fall to one half its original value, thus
Ln [A]t/[A]₀ = Ln 1/2[A]₀/[A]₀= Ln 1/2 = - kt
- 0.693 = - k(530s) ⇒ k = 1.3 x 10⁻³ s⁻¹
It’s C I think and I’m not sure
(a)The change in Gibbs free energy for the reaction has been 2.6 kJ/mol.
(b) The change in Gibbs free energy for the reaction has been -49.3 kJ/mol.
(c) The change in Gibbs free energy for the reaction has been 91.38 kJ/mol.
