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inysia [295]
3 years ago
11

What is an octet of electrons? Which elements contain an octet of electrons?

Chemistry
2 answers:
Georgia [21]3 years ago
6 0

Answer:

> Octet, in chemistry, the eight-electron arrangement in the outer electron shell of the noble-gas atoms. This structure is held responsible for the relative inertness of the noble gases and the chemical behaviour of certain other elements.

> Referring to the octet rule, atoms attempt to get a noble gas electron configuration, which is eight valence electrons. Sodium has one valence electron, so giving it up would result in the same electron configuration as neon. Chlorine has seven valence electrons, so if it takes one it will have eight (an octet).

8090 [49]3 years ago
5 0

Answer:

Explanation:

Octet, in chemistry, the eight-electron arrangement in the outer electron shell of the noble-gas atoms. This structure is held responsible for the relative inertness of the noble gases and the chemical behaviour of certain other elements.

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The standard unit for measuring made is the gram.<br><br>True or False ​
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Answer:kilogram

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4 years ago
Determine the energy of 1.70 mol of photons for each of the following kinds of light. (Assume three significant figures.)PART A
BabaBlast [244]

<u>Answer:</u>

<u>For A:</u> The energy of the given amount of photons for infrared radiation is 1.271\times 10^5J

<u>For B:</u> The energy of the given amount of photons for infrared radiation is 4.026\times 10^5J

<u>For C:</u> The energy of the given amount of photons for infrared radiation is 1.355\times 10^6J

<u>Explanation:</u>

The relationship between energy and frequency is given by Planck's equation, which is:

E=n\rimes N_A\times \frac{hc}{\lambda}        ......(1)

where,

h = Planck's constant  = 6.62\times 10^{-34}Js

E = energy of the light

c = speed of light = 3\times 10^8m/s

\lambda = wavelength of light

N_A = Avogadro's number = 6.022\times 10^{23}

n = number of moles of photons = 1.70 moles

Conversion factor used:  1m=10^9nm

  • <u>For A:</u>

Wavelength of infrared radiation = 1600nm=1.6\times 10^6m

Putting values in equation 1, we get:

E=1.7\times 6.022\times 10^{23}\times \frac{6.62\times 10^{-34}\times 3\times 10^8}{1.6\times 10^{-6}}\\\\E=1.271\times 10^5J

Hence, the energy of the given amount of photons for infrared radiation is 1.271\times 10^5J

  • <u>For B:</u>

Wavelength of visible light = 505nm=5.05\times 10^7m

Putting values in equation 1, we get:

E=1.7\times 6.022\times 10^{23}\times \frac{6.62\times 10^{-34}\times 3\times 10^8}{5.05\times 10^{-7}}\\\\E=4.026\times 10^5J

Hence, the energy of the given amount of photons for infrared radiation is 4.026\times 10^5J

  • <u>For C:</u>

Wavelength of ultraviolet radiation = 150nm=1.5\times 10^7m

Putting values in equation 1, we get:

E=1.7\times 6.022\times 10^{23}\times \frac{6.62\times 10^{-34}\times 3\times 10^8}{1.5\times 10^{-7}}\\\\E=1.355\times 10^6J

Hence, the energy of the given amount of photons for infrared radiation is 1.355\times 10^6J

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