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Lesechka [4]
3 years ago
11

14. As the temperature of a gas in a closed container increasses, what is true of the particles in the substance? (2 points)

Chemistry
1 answer:
Ede4ka [16]3 years ago
4 0
The rate of particle movement increases, also increases the pressure in the vessel
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PLZZ HELP!!!
pashok25 [27]
The sun evaporates the water from a stream or some type of water source and it then gets collected  into the clouds and then condensation and the last step is when the water is too heavy so the clouds release it and that is called precipitation. hope this helps.
5 0
3 years ago
The expected value for a chemical equation is 47g of water, after an experiment you find that you have 2.58 moles of water. What
strojnjashka [21]
<h3><u>Answer</u>;</h3>

Actual yield = 46.44 g

<h3><u>Explanation;</u></h3>

1 mole of water = 18 g/mol

Therefore;

The experimental yield = 2.58 moles

equivalent to ; 2.58 × 18 = 46.44 g

The theoretical value is 47 g

Percentage yield = 46.44/47 × 100%

                             = 98.8%

The questions asks for actual yield = 46.44 g

6 0
3 years ago
I need help with these two questions
natulia [17]
I'm not sure about 2 but in 3 it would float
8 0
3 years ago
Which best describes the trends in electronegativity on the periodic table?
Wittaler [7]

Answer:

My bad i didnt mean to put that carry on.

Explanation:

7 0
3 years ago
Read 2 more answers
Give regents and mechanism
Kryger [21]

Answer:

Reagents: 1) BH_3 2) H_2_O2, OH^-

Mechanism: Hydroboration

Explanation:

In this case, we have a <u>hydration of alkene</u>s reaction. But, in this example, we have an <u>anti-Markovnikov reaction</u>. In other words, the "OH" is added in the least substituted carbon. Therefore we have to choose an anti-Markovnikov reaction: <u>"hydroboration"</u>.

The <u>first step</u> of this reaction is the addition of borane (BH_3) to the double bond. Then in the <u>second step</u>, we have the deprotonation of the hydrogen peroxide, to obtain the peroxide anion. In the <u>third step</u>, the peroxide anion attacks the molecule produced in the first step to produce a complex compound in which we have a bond "BH_2-O-OH". In <u>step number 4</u> we have the migration of the C-B bond to oxygen. Then in <u>step number 5</u>, we have the attack of OH^- on the O-BH_2 to produce an alkoxide. Finally, the water molecule produce in step 2 will <u>protonate</u> the molecule to produce the alcohol.

See figure 1

I hope it helps!

4 0
3 years ago
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