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2 years ago

Mr. Quick bought a new computer system. The regular price was $1850, but he got a 15% discount. How much did he pay?

Mathematics

2 answers:

docker41 [41]2 years ago

8 0

He paid $1572.50 before tax

natali 33 [55]2 years ago

3 0

Answer:

the price Mr. Quick paid is=$1343

I think I can help you with this

you can easily solve this by using a rule of three

Step one

find the discount value if

$1580⇒ 100%

$x? ⇒ 15%

do the relation

the discount is $237

the price Mr. Quick paid is

the price Mr. Quick paid is=regular price - discount

the price Mr Quick paid is=$1580-$237

the price Mr Quick paid is=$1343

I hope it helps, Have a great day!!! :)

Step-by-step explanation:

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The table below represents the function F. 3 7 F(x) 4 15 5 31 7 127 8 255 The equation that represents this function is?

timurjin [86]

The table is an exponential function, and the equation that represents this function is $f(x) =2^x -1$

<h3>The equation of the table</h3>

The table is given as:

x F(x)

4 15

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Express as a base of 2

x F(x)

4 2⁴ - 1

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8 2⁸ - 1

Notice that the function is 1 subtracted from 2 raised to the power of the input.

This is represented as:

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Hence, the equation of the table is $f(x) =2^x -1$

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1 year ago

Does 3 noncollinear points always from a triangle?

Lesechka [4]

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Minimum salary is 250$. Rate of commission is 5.65% . Weekly sales are 1,515. Whats the gross pay

natali 33 [55]

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icang [17]

Answer:

$\int\limits {e^{2s} cos\frac{s}{4} ds$ = $\frac{4 e^{2s} }{65 } ({8 cos (\frac{1}{4} ) s + sin \frac{1}{4} s} ))$

Step-by-step explanation:

Step(i):-

Given that $f(s) = e^{2s} cos\frac{s}{4}$

Now integrating

$\int\limits {f(s)} \, ds = \int\limits {e^{2s} cos\frac{s}{4} ds$

By using integration formula

$\int\limits { e^{ax} cos b x dx = \frac{e^{ax} }{a^{2}+b^{2} } ( a cos b x + b sin b x )$

Step(ii):-

$\int\limits {e^{2s} cos\frac{s}{4} ds$ = $\frac{e^{2s} }{(2)^{2}+(\frac{1}{4}) ^{2} } ( 2 cos (\frac{1}{4} ) s + \frac{1}{4} sin \frac{1}{4} s ))$

= $\frac{e^{2s} }{(4+\frac{1}{16})} ( 2 cos (\frac{1}{4} ) s + \frac{1}{4} sin \frac{1}{4} s ))$

= $\frac{e^{2s} }{(\frac{65}{16} } ( \frac{8 cos (\frac{1}{4} ) s + sin \frac{1}{4} s}{4} ))$

= $16 X\frac{e^{2s} }{65 } ( \frac{8 cos (\frac{1}{4} ) s + sin \frac{1}{4} s}{4} ))$

= $\frac{4 e^{2s} }{65 } ({8 cos (\frac{1}{4} ) s + sin \frac{1}{4} s} ))$

Final answer:-

$\int\limits {e^{2s} cos\frac{s}{4} ds$ = $\frac{4 e^{2s} }{65 } ({8 cos (\frac{1}{4} ) s + sin \frac{1}{4} s} ))$

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