How does the spring constant influence the displacement? Do they increase or decrease together?

(Q004) During World War II, the military imaged the seafloor by sending pulses of sound waves down through the water and measuri

valkas [14]

Answer:

Sonar

Explanation:

Sonar is a technique that involves the use of sounds in viewing substances in a water medium to aid movement or communication. It makes use of the advantage of sound waves traveling faster and farther in water when compared to other types of waves such as light waves.

During World War II, the military employed the use of SONAR in imaging the seafloor by sending pulses of sound waves down through the water and measuring the time it took for the sound to bounce off the seafloor and return to the receiver.

7 0

3 years ago

Four uniform spheres, with masses mA = 200 kg, mB = 250 kg, mC = 1700 kg, and mD = 100 kg, have (x, y) coordinates of (0, 50 cm)

rusak2 [61]

Answer:

$F_2=2.43\times10^{-19}\ N$

$\theta=21.496^{\circ}$ in the anticlockwise direction from the positive x- axis.

Explanation:

Given are the masses of various spheres with their names in subscript:

$m_A=200\ kg$

$m_B=250\ kg$

$m_C=1700\ kg$

$m_D=100\ kg$

Now their respective coordinate positions (in cm) are as given below:

$P_A=(0,50)$

$P_B=(0,0)$

$P_C=(-80,0)$

$P_D=(40,0)$

Now force on B due to A:

$F_{BA}=G\times \frac{200\times 250}{50^2}$

$F_{BA}=20G\ N$

Now force on B due to C:

$F_{BC}=G\times \frac{1700\times 250}{80^2}$

$F_{BC}=66.406G\ N$

Now force on B due to D:

$F_{BD}=G\times \frac{100\times 250}{40^2}$

$F_{BD}=15.625G\ N$

We observe that the forces due to masses C&D act opposite in direction.

So, the net force in the x-direction:

$F_x=F_{BC}-F_{BD}$

$F_x=66.406G-15.625G$

$F_x=50.781G\ N$ in the positive x-direction

We have only one force in y-direction due to mass A.

So,

$F_y=20G\ N$ in the positive y-direction.

Now the net force:

$F_2=\sqrt{F_y^2+F_x^2}$

$F_2=\sqrt{(20G)^2+(50.781G)^2}$

$F_2=54.5776G^2\ N$

$F_2=2.43\times10^{-19}\ N$

Now the direction of this force with respect to x-axis:

$tan\ \theta=\frac{F_y}{F_x}$

$tan\ \theta=\frac{20G}{50.781G}$

$\theta=21.496^{\circ}$ in the anticlockwise direction from the positive x- axis.

3 0

3 years ago

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Match the process with the fundamental interaction responsible for this process.

Phantasy [73]

Answer:

a - 3 , b - 2 , c-- 2 , d - 1

Explanation:

In this exercise we must relate the different physical processes with the force responsible for the process:

a. Neutron decay

the disintegration of the neutral is an example of the weak interaction

a - 3

b. The Earth pulls the Moon.

In this case as the two bodies and with great mass, the interaction is the gravitational interaction

b - 2

c. gravitational interaction

c-- 2

d. Protons repel other protons in the nucleus.

Since the two particles have a positive charge, the interaction is electromagnetic

d - 1

missing the case of the strong interaction that is responsible for the attraction of proton proton and proton neutron within the nucleus

7 0

3 years ago

A projectile is launched with an initial velocity 60m/s at an angle 60° to the vertical. What the magnitude of it's displacement

emmasim [6.3K]

Answer:

the magnitude of the displacement after 5s is 137.31 m.

Explanation:

Given;

initial velocity of the projectile, u = 60 m/s

angle of projection, θ = 60°

time of motion, t = 5s

the vertical component of the velocity, $u_y= u\ sin \theta = 60sin(60^0)$

The magnitude of the displacement after 5s is calculated as;

$h = u_yt -\frac{1}{2} gt^2\\\\h = 60sin (60^0)\times 5 - \frac{1}{2} (9.8)(5)^2\\\\h = 259.81-122.5\\\\h = 137.31 \ m$

Therefore, the magnitude of the displacement after 5s is 137.31 m.

3 0

3 years ago

If a steel nail is wrapped 8 times with an insulated copper wire and each end of is attached to a 1.5 V battery, we find that it

sergejj [24]

Answer:

2

Explanation:

i think that it would be 2 because it makes the most sense

4 0

3 years ago

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