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Aleks [24]
3 years ago
13

How does the spring constant influence the displacement? Do they increase or decrease together?

Physics
1 answer:
harina [27]3 years ago
5 0

Explanation:

I have asked question in my profile please tell me the answer

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Predict which molecule will show a similar relationship between its heat of fusion and its heat vaporization that water does
BaLLatris [955]

Question:

A) C6H6

B) CH3CH2CH2CH2CH2COH6

C) NaCl

D) NH3

Answer:

The correct option is;

A) C₆H₆

Explanation:

Heat of fusion = 6.02 kJ/mol

Heat of vaporization =40.8 kJ/mol

Here, we analyze each of the options as follows

A) C₆H₆

Benzene has a melting point of 5.5° C and a boiling point of

80.1 ° C similar to water

Heat of fusion = 9.92 kJ/mol

Heat of vaporization =30.8kJ/mol

B) CH₃CH₂CH₂CH₂CH₂COH₆

The above compound is more likely solid

C) NaCl solid

D) NH₃ melting point = -77.73 °C boiling point =  -33.34 °C

Of the above, the compounds the one  that closely resembles water is C₆H₆

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How images from space of earth and other objects are useful
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To show stuff that we cant see in very well
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3 years ago
What is a vector? Please help!
Len [333]
A quantity having direction as well as magnitude,especially as determining the position of one point in space relative to another.
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3 years ago
Two cars, A and B , travel in a straight line. The distance of A from the starting point is given as a function of time by xA(t)
OLga [1]

A) Car A is initially ahead

B) The two cars are at the same point at the times: t = 0, t = 2.27 s and

t = 5.73 s

C) The distance between the two cars is not changing at t = 1.00 s and t = 4.33 s

D) The two cars have same acceleration at t = 2.67 s

Explanation:

A)

The position of the two cars at time t is given by the following functions:

x_A(t) = \alpha t + \beta t^2

with

\alpha = 2.60 m/s\\\beta = 1.20 m/s^2

Substituting,

x_A(t)=2.60t+1.20 t^2

And

x_B(t)=\gamma t^2 - \delta t^3

with

\gamma=2.80 m/s^2\\\delta = 0.20 m/s^3

Substituting,

x_B(t)=2.80t^2-0.20t^3

Here we want to find which car is ahead just after they leave the starting point. To find that, we just need to calculate the position of the two cars after a very short amount of time, let's say at t = 0.1 s. Substituting this value into the two equations, we get:

x_A(0.1)=2.60(0.1)+1.20(0.1)^2=0.27 m

x_B(0.1)=2.80(0.1)^2-0.20(0.1)^3=0.03 m

So, car A is initially ahead.

B)

The two cars are at the same point when their position is the same. Therefore, when

x_A(t)=x_B(t)

which means when

2.60t+1.20t^2 = 2.80t^2-0.20t^3

Re-arranging the equation, we find

0.20t^3-1.6t^2+2.60t=0\\t(0.20t^2-1.6t+2.60)=0

One solution of this equation is t = 0 (initial point), while we have two more solutions given by the equation

0.20t^2-1.6t+2.60=0

which has two solutions:

t = 2.27 s

t = 5.73 s

So, these are the times at which the cars are at the  same point.

C)

The distance between the two cars A and B is not changing when the velocities of the two cars is the same.

The velocity of car A is given by the derivative of the position of  car A:

v_A(t) = x_A'(t)=(2.60t+1.20t^2)'=2.60+2.40t

The velocity of car B is given by the derivative of the position of car B:

v_B(t)=x_B'(t)=(2.80t^2-0.20t^3)'=5.60t-0.60t^2

Therefore, the distance between the two cars is not changing when the two velocities are equal:

v_A(t)=v_B(t)\\2.60+2.40t=5.60t-0.60t^2\\0.60t^2-3.20t+2.60=0

This is another second-order equation, which has two solutions:

t = 1.00 s

t = 4.33 s

D)

The acceleration of each car is given by the  derivative of the velocity of the car A.

The acceleration of car A is:

a_A(t)=v_A'(t)=(2.60+2.40t)'=2.40

While the acceleration of car B is:

a_B(t)=v_B'(t)=(5.60t-0.60t^2)'=5.60-1.20t

So, the two cars have same acceleration when

a_A(t)=a_B(t)

And solving the equation, we find:

2.40=5.60-1.20t\\1.20t=3.20\\t=2.67 s

So, the two cars have same acceleration at t = 2.67 s.

Learn more about accelerated motion:

brainly.com/question/9527152

brainly.com/question/11181826

brainly.com/question/2506873

brainly.com/question/2562700

#LearnwithBrainly

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What does Newton’s law of universal gravitation say about the distance between objects?
satela [25.4K]

It says: The bigger the distance between objects the smaller the gravity between them.

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