There are several formulas that describe the distance, speed, and time for
a falling body. The one I use the most happens to be the one that'll be the
most useful to solve this problem:
Distance = 1/2 g t²
We know the distance and we know ' g ', so we can use
this formula to find ' t '.
Distance = (1/2) (gravity) (time)²
(239 m) = (1/2) (3.7 m/s²) (time)²
Divide each side
by 1.85 m/s² : (129 m) / (1.85 m/s²) = (time)²
(129/1.85) sec² = (time)²
Take the square root
of each side: 8.35 sec = time
Answer:
21.53 x 10^{6} N
Explanation:
force (F) = 4.71 x 10^{3} N
distance (s) = 4.57 km = 4570 m
how much work is done.
work = force x distance
work = 4.71 x 10^{3} x 4570 = 21.53 x 10^{6} N
okay u need to use the equation m=Fnet/a. Fnet=540N a=7.74m/s^2 m=540N/7.74m/s^2=69.77kg
