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Gnoma [55]
2 years ago
11

What is peer review.why is it important​

Physics
2 answers:
madam [21]2 years ago
6 0

Acc to

Publisso

Peer review is subjecting the author's scholarly work and research to the scrutiny of other experts in the same field to check its validity and evaluate its suitability for publication.

A peer review helps the publisher decide whether a work should be accepted.

Lena [83]2 years ago
6 0

Answer:

your showing facts

Explanation:

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A person is walking briskly in a straight line. The figure shows a graph of the person’s position x as a function of time t. Wha
Nina [5.8K]

The average velocity over the interval 6\le t\le 10 is

\dfrac{x(10)-x(6)}{10\,\mathrm s-6\,\mathrm s}=\dfrac{6\,\mathrm m-2.67\,\mathrm m}{4\,\mathrm s}=0.8325\,\dfrac{\mathrm m}{\mathrm s}

where x(t) is the person's position at time t. I've taken the liberty of estimating x(6)\approx2.67\,\mathrm m. The closest choice among the answers is 0.8\,\dfrac{\mathrm m}{\mathrm s}.

7 0
2 years ago
1.Sobre a queda-livre,assinale V para verdadeiro e F para falso
lisov135 [29]

Answer:pelo o que eu sei é ..

V

V

V

F

F

F

Explanation:

8 0
3 years ago
A basketball player spins the ball with an angular acceleration of 10 rad/s2. What is the ball’s final angular velocity if the b
Lena [83]

Explanation:

It is given that,

The angular acceleration of the basketball, \alpha=10\ rad/s^2

Time taken, t = 3 seconds

We need to find the ball’s final angular velocity if the ball starts from rest. It can be calculated using definition of angular acceleration i.e.

\alpha=\dfrac{\omega_f-\omega_i}{t}

\omega_i=0\ (rest)

\omega_f=\alpha t

\omega_f=10\ rad/s^2\times 3\ s

\omega=30\ rad/s

So, the ball's final angular velocity is 30 rad/s. Hence, this is the required solution.

8 0
2 years ago
The froghopper Philaenus spumarius is supposedly the best jumper in the animal kingdom. To start a jump, this insect can acceler
Kay [80]

Answer:

Part a)

v_f = 4 m/s

Part b)

t = 0.001 s

Part c)

d = 0.815 m

Explanation:

Part a)

As we know that initially the grass hopper is at rest at the ground position

Now the acceleration is given as

a = 4000 m/s^2

distance of the legs that it stretched is given as

s = 2.0 mm

so we have

v_f^2 - v_i^2 = 2 a d

v_f^2 - 0 = 2(4000)(0.002)

v_f = 4 m/s

Part b)

time taken to reach this speed is given as

v_f - v_i = at

4 - 0 = 4000 t

t = 0.001 s

Part c)

as the grass hopper reach the maximum height its final speed would be zero

so we will have

v_f^2 - v_i^2 = 2 a d

0 - 4^2 = 2(-9.81) d

d = 0.815 m

5 0
3 years ago
Can someone please answer?
nevsk [136]
The answer to your problem is I believe (B.)
5 0
2 years ago
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