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Arisa [49]
3 years ago
12

Use the following information about Earth and its moon to determine the distance between them. Earth's mass = 6.0 x 1024 kg Moon

's tangential speed = 1,025 m/s Earth's radius = 6.4 x 10 m Moon's mass = 7.3 X 1022 kg 4.6 x 106 m O 3.8 x 108 m O 3.9 x 1011 m​
Physics
2 answers:
MrRissso [65]3 years ago
6 0

Answer:

the planet Uranus has mass 8.7 x 1025 kg. ... radius 5.1 x 107 m around Uranus. G= 6.7 x ... The gravitational potential of the satellite is its centripetal force. ... Moon. Use this idea to calculate the mass of the Earth M from the values of vand rgiven ... 9mm . Ve GM. Ma var. 1023** 3-8* 10". M= ... 5.9x1024... kg [2]. 6-7x 10-11.

9966 [12]3 years ago
5 0

Answer:

3.8 × 108 m

Explanation:

Use formula: v^2 = G x m central / r

G = 6.77 e-11

Also, it was right on Edge.

Good luck!

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Read 2 more answers
While vacationing in the mountains you do some hiking. In the morning, your displacement is S⃗ morning= (2200 m , east) + (4000
Minchanka [31]

Answer:

a

    The hiker (you ) is  200 m below his/her(your) starting point

b

   The resultant displacement in the north east direction is

a  = 6562.0 \  m

    The resultant displacement in vertical direction (i.e the altitude change )

  b =6503.1 \  m

Explanation:

From the question we are told that  

  The displacement in the morning is  S_{morning} =  (2200 \m , east) + (4000\ m\ north) + (100 \ m ,\ vertical)

   The displacement in the afternoon is  S _{afternoon}= (1300\ m ,\ west) + (2500 \ m ,\ north) - (300\ m ,\ vertical)

Generally the direction west is negative , the direction east is positive

                 the direction south is negative , the direction north is  positive

resultant displacement  is mathematically evaluated as  

    (2200 \m , east) +( - 1300\ m ,\ west) = 900 \ m \ east

     (4000\ m\ north)  + (2500 \ m ,\ north) = 6500  \ m ,\ north

     (100 \ m ,\ vertical) - (300\ m ,\ vertical) = -200 \ m

From the above calculation we see that at the end of the hiking the hiker (you) is  200 m below his/her(your) initial position

Generally from Pythagoras theorem , the resultant displacement in the north east direction is

      a  =  \sqrt{900^2 + 6500^2}

=>     a  = 6562.0 \  m

Generally from Pythagoras theorem , the resultant displacement in vertical direction (i.e the altitude change )

      b = \sqrt{6500^2 +(-200)^2  }

=>   b =6503.1 \  m

   

5 0
3 years ago
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