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3 years ago

Explain all the energy conversions that take place while using a cell phone.

Physics

1 answer:

zhuklara [117]3 years ago

8 0

Answer:

#See solution for details.

Explanation:

-Chemical energy in the battery is converted into Electrical Energy which powers up the phone.

-The electrical energy is then converted to Light Energy when the phone is powered up, this is seen through the lightening up of the phone screen.

-During phone calls, the electrical energy is further converted to Sound Energy to allow for transmission of audio signals.

- As we continue to use the phone, the electrical energy is converted into heat energy which we feel due to an overheating battery.

-The cycle then repeats itself again whenever a phone is charged.

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A particle is being accelerated through space by a 10 N force. Suddenly the particle encounters a second of 10 N force in the op

Lyrx [107]

Answer:

The particle will be rendered still

Explanation:

The particle will be rendered still because of the Newton’s 1st law of motion states that a body will continue to move on forever until contacted by an equal and opposite force. The same case has been produced here and it is justifying the law. If the Force has another direction and magnitude than 10 N then the body will continue to move on in the direction of the greater force.

7 0

3 years ago

An oxygen atom at a particular site within a DNA molecule can be made to execute simple harmonic motion when illuminated by infr

lukranit [14]

Answer:

The frequency of the sulphur is 2.6×10^13 Hz.

We find the frequency of the sulphur because sulphur is just below the oxygen atom in the periodic table. So, we find it by using the frequency of the oxygen.

Explanation:

As, the frequency in terms of spring constant and mass is :

f = (1/2π) × √(k/m)

k is the spring constant and m is the mass.

Square on both sides of the equation and it becomes then,

f^2 = (1/4π^2) × (k/m)

f^2×m = k/4π^2

Now, we will solve it with oxygen and sulphur because the oxygen atom is chemically replaced with a sulphur atom, the spring constant of the bond is unchanged so, the relation between fo and fs is:

As, fo is the frequency of the oxygen and fs is the frequency of the sulphur atom and mo is the mass of the oxygen and ms is the mass of the sulphur.

So,

fs^2 = (fo^2×mo) / ms

fs = fo×√(mo/ms)

As, we also know the mass of the oxygen and sulphur which is 16amu and 32amu:

fs = (3.7×10^13) × √(16/32)

fs = (3.7×10^13) × 1/√2

fs = 2.6×10^13 Hz.

Therefore, the frequency is: 2.6×10^13 Hz.

4 0

3 years ago

Objects 1 and 2 attract each other with a gravitational force of 72.0 units. If the mass of Object 1 is one-fourth the original

Black_prince [1.1K]

Answer:

New gravitational force, F' = 216 units

Explanation:

Given that,

Gravitational force between object 1 and 2, F = 72 N

The gravitational force between two objects is given by :

$F=\dfrac{Gm_1m_2}{r^2}$

$\dfrac{Gm_1m_2}{r^2}=72$ ............(1)

If the mass of object 1, $m_1'=\dfrac{m_1}{4}$

$m_2'=3m_2$

If the distance between objects is halved, $r'=\dfrac{r}{2}$

Let new gravitational force is F'. It is changed to :

$F=\dfrac{Gm'_1m'_2}{r'^2}$

$F'=\dfrac{G\times \dfrac{m_1}{4}\times 3m_2}{(\dfrac{r}{2})^2}$

$F'=3\times \dfrac{Gm_1m_2}{r^2}$

$F'=3\times F$

$F'=3\times 72$

F' = 216 units

So, the new gravitational force will be 216 units.

6 0

3 years ago

HELP ASAP HELP Two tennis balls of the same mass are served at different speeds: 30 m/s and 60 m/s. Which serve has more kinetic

inna [77]

Answer:

<em>The second ball has four times as much kinetic energy as the first ball.</em>

Explanation:

<u>Kinetic Energy </u>

Is the type of energy an object has due to its state of motion. It's proportional to the square of the speed.

The equation for the kinetic energy is:

$\displaystyle K=\frac{1}{2}mv^2$

Where:

m = mass of the object

v = speed at which the object moves

The kinetic energy is expressed in Joules (J)

Two tennis balls have the same mass m and are served at speeds v1=30 m/s and v2=60 m/s.

The kinetic energy of the first ball is:

$\displaystyle K_1=\frac{1}{2}m\cdot 30^2$

$\displaystyle K_1=\frac{1}{2}m\cdot 900$

$K_1=450m$

The kinetic energy of the second ball is:

$\displaystyle K_2=\frac{1}{2}m\cdot 60^2$

$\displaystyle K_2=\frac{1}{2}m\cdot 3600$

$K_2=1800m$

Being m the same for both balls, the second ball has more kinetic energy than the first ball.

To find out how much, we find the ratio:

$\displaystyle \frac{K_2}{K_1}=\frac{1800m}{450m}$

Simplifying:

$\displaystyle \frac{K_2}{K_1}=4$

The second ball has four times as much kinetic energy as the first ball.

5 0

3 years ago

Read 2 more answers

Round to three significant figures.<br> 0.0785584 rounds to

Elan Coil [88]

Answer:

0.0786

Explanation:

zero after the decimal place is not a significant figure since it comes before the real integer "7".

"5 " in ten thousandth place is rounded off to "6" because the next digit is also another "5",

so we get the three sfg 0.0786

8 0

3 years ago