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3 years ago

How many meters of wrapping paper is needed to cover a present of this shape?

Mathematics

2 answers:

irga5000 [103]3 years ago

5 0

Hey , here it is!!
Can u give me a brainliest answer????

U can calculate the hight with tha pitagoras theorem:
x^2=5^2*13^2
x=square root of 65

sattari [20]3 years ago

4 0

Answer:

what are the options????

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Solve by the method of balancing and equation and write the step use to separate the variable.....

lesya [120]

Answer:

the required answers are :

c) x = 2

d) x = 27 / 7

e) x = 9

f ) x = 6

Step-by-step explanation:

for explanation see the attached image

^_^

5 0

3 years ago

Aluminum gold is 22% aluminum; the rest is gold. If aluminum gold bar contains 55g of aluminum, how many grams of gold does it c

Katarina [22]

195 grams 55/250=.22% 250-55=195g gold

7 0

3 years ago

Reduce -7/8 + (-1/2) to the simplest form.

ololo11 [35]

Answer:

-1.375

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Average precipitation for the first 7 months of the year, the average precipitation in toledo, ohio, is 19.32 inches. if the ave

Colt1911 [192]

Part A:

The probability that a normally distributed data with a mean, μ and standard deviation, σ is greater than a given value, a is given by:

$P(x\ \textgreater \ a)=1-P(x\ \textless \ a)=1-P\left(z\ \textless \ \frac{a-\mu}{\sigma}\right)$

Given that the average precipitation in Toledo, Ohio for the past 7 months is 19.32 inches with a standard deviation of 2.44 inches, the probability that <span>a randomly selected year will have precipitation greater than 18 inches for the first 7 months is given by:

$P(x\ \textgreater \ 18)=1-P(x\ \textless \ 18) \\ \\ =1-P\left(z\ \textless \ \frac{18-19.32}{2.44}\right) \\ \\ =1-P(z\ \textless \ -0.5410) \\ \\ =1-0.29426=\bold{0.7057}$

Part B:

</span>The probability that an n randomly selected samples of a normally distributed data with a mean, μ and standard deviation, σ is greater than a given value, a is given by:

$P(x\ \textgreater \ a)=1-P(x\ \textless \ a)=1-P\left(z\ \textless \ \frac{a-\mu}{\frac{\sigma}{\sqrt{n}}}\right)$

Given that the average precipitation in Toledo, Ohio for the past 7 months is 19.32 inches with a standard deviation of 2.44 inches, the probability that <span>5 randomly selected years will have precipitation greater than 18 inches for the first 7 months is given by:

</span> $P(x\ \textgreater \ 18)=1-P(x\ \textless \ 18) \\ \\ =1-P\left(z\ \textless \ \frac{18-19.32}{\frac{2.44}{\sqrt{5}}}\right) \\ \\ =1-P(z\ \textless \ -1.210) \\ \\ =1-0.1132=\bold{0.8868}$

7 0

3 years ago

A circular room at an office has a diameter of 96 feet. What is the area of the floor in the room? Use 3.14 to approximate pi. R

tia_tia [17]

The area of the floor in the room would be 7,234.56 feet. This is found by multiplying 3.14 by the radius (48) squared, or (3.14)(48)^2=7,234.56.

5 0

3 years ago