Answer:
a)= 2
b) 6.324
c) P= 0.1217
Step-by-step explanation:
a) The mean of the sampling distribution of X`1- X`2 denoted by ux`-x` = u1-u2 is equal to the difference between population means i.e = 2 ( given in the question)
b) The standard deviation of the sampling distribution of X`1- X`2 ( standard error of X`1- X`2) denoted by σ_X`1- X`2 is given by
σ_X`1- X`2 = √σ²/n1 +σ²/n2
Var ( X`1- X`2) = Var X`1 + Var X`2 = σ²/n1 +σ²/n2
so
σ_X`1- X`2 =√20 +20 = 6.324
if the populations are normal the sampling distribution X`1- X`2 , regardless of sample sizes , will be normal with mean u1-u2 and variance σ²/n1 +σ²/n2.
Where as Z is normally distributed with mean zero and unit variance.
If we take X`1- X`2= 0 and u1-u2= 2 and standard deviation of the sampling distribution = 6.324 then
Z= 0-2/ 6.342= -0.31625
P(-0.31625<z<0)= 0.1217
The probability would be 0.1217
3/5 = 60%
20 ÷ 5 = 4
3 x 4 = 12
Answer is A) 12/20
Answer:
Range is 3 <= g(x) <= 27.
Step-by-step explanation:
The range is the values of g(x) for the given domain.
When x = 0 g(x) = 3(0)^2 - 6(0) + 3 = 3.
When x = 4 g(x) = 3(4)^2 - 6(4) + 3 = 27.
Sorry didn't know how to write the answer so I just took a screen shot of my answer for you!
