The probability that the train will be there when Alex arrives is 5/18
If Alex arrives at any time after 1.20pm the chances that train will be there is 1/3.
However if alex arrives at 1.00pm exactly there is no chance the train will be arrive there.
The probability that the train will be there increase linearly to 1/3 as alex's arrival time moves from 1.00pm to 1.20pm.
By arranging the probabilities over the first 20 minutes to get a 1/6 chance the train will be there if alex arrives between 1.00pm to 1.20pm
we get the final answer by
=1/3( 1/6 + 1/3 + 1/3)
=5/18
So, the probability that the train will be there when Alex arrives is 5/18
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Answer:
I’m pretty sure it’s 73% but I’m not completely sure
Answer:
4/7
Step-by-step explanation:
2/7 ÷1/2=2/7 × 2 = 4/7
Hope this helps :D
First, make an organized list of the factors for each number. The common factors are 1, 2, 4, 8, and 16, and the greatest of these is 16. So, the greatest common factor or GCF of 48 and 64 is 16.
Answer:
104
Step-by-step explanation:
PEMDAS, do the multiplication first and then the addition
