Is the relationship shown by the data linear? If so, model the data with an equation.
1 answer:
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Answer:
13, 14, 15, 16
Step-by-step explanation:
Call the first number n. Then the next three consecutive numbers (assuming integers) are n + 1, n + 2, n + 3.
The mean is the total of the numbers divided by how many there are.
Simplify and multiply by 4.
The first number is 13.
The median is 14.5, halfway between the "middle" numbers 14 and 15. This is just a check; no additional equation is necessary.
Let's make the first even integer m and the second even integer n. The square of the first, decreased by the second is 130 is:
-n=130 ---> Add n to each side
=130+n ---> Take the square root of each side
m=±
Let's look at the first square number above 130, which is
. <em>m</em> is 12, therefore the next consecutive even integer is 14.
=144
144-14=130
The two consecutive integers are 12 and 14
m=±
Let's look at the first square number above 130, which is
144-14=130
The two consecutive integers are 12 and 14