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3 years ago

8

Help me, please... Which two numbers on the number line have an absolute value of 2.75? Select the location of both numbers on t

he number line.

1 answer:

Fofino [41]3 years ago

6 0

Answer:

2.75, and - 2.75

Step-by-step explanation:

Both have an absolute value of 2.75 which is how far away they are from 0.

Hope this helped!

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Please help me!!!!!!!!

Bezzdna [24]

Answer:

(3·x + 6) + (7·x + 4) = 180 --> x = 17

3·17 + 6 = 57

Answer D is correct.

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3 years ago

2 log x + log 11<br> WILL MARK BRAINLIEST

tester [92]

Answer:

$log(11 {x}^{2} )$

Step-by-step explanation:

$2logx + log11 \\ \\ = log {x}^{2} + log11 \\ \\ = log( {x}^{2} \times 11) \\ \\ = log(11 {x}^{2} )$

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3 years ago

6.493 rounded to the hundredths

Nana76 [90]

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3 years ago

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Kazeer [188]

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3 years ago

Difference in the following polynomials (6x^3 - 2x^2 + 4)<br> -(2x^3 + 4x^2 - 5)

Colt1911 [192]

$\bold{[ \ Answer \ ]}$

$\boxed{\bold{4x^3-6x^2+9}}$

$\bold{[ \ Explanation \ ]}$

$\bold{Find \ Difference: \ \left(6x^3\:-\:2x^2\:+\:4\right)-\left(2x^3\:+\:4x^2\:-\:5\right)}$

$\bold{-----------------------}$

$\bold{Remove \ Parenthesis}$

$\bold{6x^3-2x^2+4-\left(2x^3+4x^2-5\right)}$

$\bold{Remove \ Parenthesis \ / \ Simplify}$

$\bold{-\left(2x^3+4x^2-5\right): \ -2x^3-4x^2+5}$

$\bold{Rewrite}$

$\bold{6x^3-2x^2+4-2x^3-4x^2+5}$

$\bold{[Simplify \ 6x^3-2x^2+4-2x^3-4x^2+5] \ 4x^3-6x^2+9}$

$\bold{4x^3-6x^2+9}$

$\boxed{\bold{[] \ Eclipsed \ []}}$

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3 years ago