Suppose a free-fall ride at an amusement park starts at rest and is in free fall. What is the velocity of the ride after 2.3 s?
1 answer:
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Answer:
125.83672 seconds
Explanation:
P = Power of the horse = 1 hp = 746 W (as it is not given we have assumed the horse has the power of 1 hp)
m = Mass of professor = 103 kg
g = Acceleration due to gravity = 9.8 m/s²
h = Height of professor = 93 m
Work done would be equal to the potential energy
Power is given by
The time taken by the horse to pull the professor is 125.83672 seconds
Answer:
Final velocity v = 8.944 m/sec
Explanation:
We have given distance S = 40 meters
Time t = 10 sec
As it starts from rest so initial velocity u = 0
From second equation of motion
Now from first equation of motion , here v is final velocity, u is initial velocity, a is acceleration and t is time
So
Answer:
The mass m is 0.332 kg or 332 gm
Explanation:
Given
The platform is rotating with angular speed ,
Mass m is moving on platform in a circle with radius ,
Force sensor reading to which spring is attached ,
Now for the mass m to move in circle the required centripetal force is given by
=>
Thus the mass m is 0.332 kg or 332 gm