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Artist 52 [7]
3 years ago
11

Write the answer:physics ... i need help ​

Physics
1 answer:
Mariana [72]3 years ago
7 0

Answer:

6 gallons

Explanation:

At 30 mph, the fuel mileage is 25 mpg.

After 5 hours, the distance traveled is:

30 mi/hr × 5 hr = 150 mi

The amount of gas used is:

150 mi × (1 gal / 25 mi) = 6 gal

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A wire 25.0cm long lies along the z-axis and carries a current of 9.00A in the positive +z-direction. The magnetic field is unif
marysya [2.9K]

The expression of the magnetic force and solving the determinant allows to shorten the result for the value of the magnetic force are:

  • In Cartesian form  F = 2.46 i ^ - 0.605 j ^
  • In the form of magnitude and direction F = 2.53 N and θ = 346.2º

Given parameters.

  • Length of the wire on the z axis is: L = 25.0 cm = 0.25 m.
  • The current i = 9.00 A in the positive direction of the z axis.
  • The magnetic field B = (-0.242 i ^ - 0.985 j ^ -0.336 k ^ ) T

To find.

  • Magnetic force.

The magnetic force on a wire carrying a current is the vector product of the direction of the current and the magnetic field.

          F = i L x B

Where the bold letters indicate vectors, F is the force, i the current, L a vector pointing in the direction of the current and B the magnetic field.

The best way to find the force is to solve the determinant, in general, a vector (L) is written in the form of the module times a <em>unit vector</em>.

         F= i |L| \left[\begin{array}{ccc}i&j&k\\L_x&L_y&L_z\\B_x&B_y&B_z\end{array}\right]  

Let's calculate.

       F= 9.00  \ 0.25 \ \left[\begin{array}{ccc}i&j&k\\0&0&1\\-0.242&-0.985&-0.336\end{array}\right]  

       F = 2.26 \ ( - 1 B_y i  \   + 1 B_x j  \ )  

       F = 2.5 (0.985 i ^ - 0.242 j ^)

       F = ( 2.46 i ^ - 0.605 j^ ) N

To find the magnitude we use the Pythagorean theorem.

        F = \sqrt{F_x^2 + F_y^2}  

        F = \sqrt{2.46^2 + 0.605^2}  

        F = 2.53 N

Let's use trigonometry for the direction.

        Tan θ ’= \frac{F_y}{F_x}  

        θ'= tan⁻¹ \frac{F_y}{F_x}  

        θ'= tan⁻¹1 (\frac{-.605}{2.46} )

        θ’= -13.8º

To measure this angle from the positive side of the x-axis counterclockwise.

        θ = 360- θ'

        θ = 360 - 13.8

        θ = 346.2º

In conclusion using the expression of the magnetic force and solving the determinant we can shorten the result for the value of the force are:

  • In Cartesian form    F = 2.46 i ^ - 0.605 j ^
  • In the form of magnitude and direction  F = 2.53 N and θ = 346.2º

Learn more here:  brainly.com/question/2630590

5 0
2 years ago
Calculate the capacitance of a system that stores 9.4 x 10-10 C of charge at
pantera1 [17]

The capacitance of the system is 1.9\cdot 10^{-11}F

Explanation:

The capacitance of a capacitor is given by the following equation:

C=\frac{Q}{V}

where

C is the capacitance

Q is the charge stored in the capacitor

V is the potential difference across the capacitor

In this problem, we have:

Q=9.4\cdot 10^{-10}C is the charge stored

V=50.0 V is the potential difference across it

Substituting into the equation, we find the capacitance:

C=\frac{9.4\cdot 10^{-10}}{50.0}=1.9\cdot 10^{-11}F

Learn more about capacitors:

brainly.com/question/10427437

brainly.com/question/8892837

brainly.com/question/9617400

#LearnwithBrainly

7 0
3 years ago
Read 2 more answers
When placed near another charge, a 20 microcoulomb charge experiences an attractive force of 0.080 N. What is the electric field
prohojiy [21]

Answer:

E = 4000 N/C

Explanation:

Given the following data;

Force = 0.080 N.

Charge, q = 20 microcoulomb = 20 * 10^-6 = 2 * 10^-5 Coulombs

To find the electric field strength;

Mathematically, the electric field strength is given by the formula;

Electric field strength = force/charge

Substituting into the formula, we have;

E = 0.080/0.00002

E = 4000 N/C

8 0
3 years ago
The velocity of a motor bike of mass 140 kg is increased to 40m/s from 20m/s in 2 seconds. Then the force required for this is?
Liula [17]

Answer:

true blood season and answers the question of whether you are not the intended recipient you are not the intended recipient you are not the intended recipient

5 0
3 years ago
The atmospheric pressure on the top of the Engineering Sciences Building (ESB) is 97.6 kPa, while that in Room G39-ESB (ground f
Stells [14]

Answer:

Δ h = 52.78 m

Explanation:

given,

Atmospheric pressure at the top of building = 97.6 kPa

Atmospheric pressure at the bottom of building = 98.2 kPa

Density of air = 1.16 kg/m³

acceleration due to gravity, g = 9.8 m/s²

height of the building = ?

We know,

Δ P = ρ g Δ h

(98.2-97.6) x 10³ = 1.16 x 9.8 x Δ h

11.368 Δ h = 600

Δ h = 52.78 m

Hence, the height of the building is equal to 52.78 m.

6 0
3 years ago
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