1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
marshall27 [118]
2 years ago
10

What factors affect the strength and direction of electrical forces?

Physics
1 answer:
nadezda [96]2 years ago
4 0

Answer:

The strength of the electric field is determined by the amount of charge on the source charge (Q) and the separation distance (d) from the source charge.

Explanation:

The interaction of charged objects is a non-contact force that operates over a certain separation distance. Distance, distance, distance. Every electrical contact is accompanied by a force, emphasizing the significance of these three factors. Whether it's a plastic golf tube attracting paper bits, two like-charged balloons repelling, or a charged Styrofoam plate interacting with electrons in a piece of metal, the three crucial factors that impact the strength of the interaction are always two charges and a distance between them.  The electrical force, like all other forces, is usually measured in Newtons. The electrical interaction's intensity is a vector quantity with both magnitude and direction since it is a force. The electrical force's direction is determined by whether the charged objects are charged with similar or opposing charges, as well as their spatial orientation. With a little logic and knowledge of the two objects' charge types, the direction of the force on either of them may be determined. Objects A and B in the figure below have similar charges, hence they repel each other.

You might be interested in
PLEASE ASAP ILL GIVE BRAINLIEST.
Olegator [25]

Answer:

The answer is number 2 :)

8 0
3 years ago
Read 2 more answers
A uniformly charged ring of radius 10.0 cm has a total charge of 75.0 mC. Find the electric field on the axis of the ring at (a)
wlad13 [49]

Answer:

(a) 6650246.305 N/C

(b) 24150268.34 N/C

(c) 6408227.848 N/C

(d) 665024.6305 N/C

Explanation:

Given:

Radius of the ring (r) = 10.0 cm = 0.10 m           [1 cm = 0.01 m]

Total charge of the ring (Q) = 75.0 μC = 75\times 10^{-6}\ \mu C    [1 μC = 10⁻⁶ C]

Electric field on the axis of the ring of radius 'r' at a distance of 'x' from the center of the ring is given as:

E_x=\dfrac{kQx}{(x^2+r^2)^\frac{3}{2}}

Plug in the given values for each point and solve.

(a)

Given:

Q=75\times 10^{-6}\ \mu C, r=0.01\ m, a=1.00\ cm=0.01\ m,k=9\times 10^{9}\ Nm^2/C^2

Electric field is given as:

E_x=\dfrac{(9\times 10^{9})(75\times 10^{-6})(0.01)}{((0.01)^2+(0.1)^2)^\frac{3}{2}}\\\\E_x=\dfrac{6750}{1.015\times 10^{-3}}\\\\E_x=6650246. 305\ N/C

(b)

Given:

Q=75\times 10^{-6}\ \mu C, r=0.01\ m, a=5.00\ cm=0.05\ m,k=9\times 10^{9}\ Nm^2/C^2

Electric field is given as:

E_x=\dfrac{(9\times 10^{9})(75\times 10^{-6})(0.05)}{((0.05)^2+(0.1)^2)^\frac{3}{2}}\\\\E_x=\dfrac{33750}{1.3975\times 10^{-3}}\\\\E_x=24150268.34\ N/C

(c)

Given:

Q=75\times 10^{-6}\ \mu C, r=0.01\ m, a=30.0\ cm=0.30\ m,k=9\times 10^{9}\ Nm^2/C^2

Electric field is given as:

E_x=\dfrac{(9\times 10^{9})(75\times 10^{-6})(0.30)}{((0.30)^2+(0.1)^2)^\frac{3}{2}}\\\\E_x=\dfrac{202500}{0.0316}\\\\E_x=6408227.848\ N/C

(d)

Given:

Q=75\times 10^{-6}\ \mu C, r=0.01\ m, a=100\ cm=1\ m,k=9\times 10^{9}\ Nm^2/C^2

Electric field is given as:

E_x=\dfrac{(9\times 10^{9})(75\times 10^{-6})(1)}{((1)^2+(0.1)^2)^\frac{3}{2}}\\\\E_x=\dfrac{675000}{1.015}\\\\E_x=665024.6305\ N/C

7 0
3 years ago
The y-axis on a distance-time graph would be ____________. time distance speed
natita [175]

Answer:

Distance

Explanation:

distance is in vertical axis,or y-axis and time is on the horizontal axis,or x-axis.

7 0
3 years ago
When nuclear fission occurs some mass is lost where does that mass go
horrorfan [7]
The loss of matter is called the mass defect. The missing matter is converted into energy. You can actually calculate the amount of energy produced during a nuclear reaction with  fairly simple equation developed by Albert Einstein; E = mc^2. In this equation, E is the amount of energy produced, m is the missing mass, or the mass defect, and c is the speed of light, which is a rather large number. The speed of light is squared, making that part of the equation a very large number that, even when multiplied by a small amount of mass, yields a large amount of energy.
4 0
3 years ago
Read 2 more answers
State the law of conservation of energy​
storchak [24]

Answer:

In physics and chemistry, the law of conservation of energy states that the total energy of an isolated system remains constant; it is said to be conserved over time. ... For instance, chemical energy is converted to kinetic energy when a stick of dynamite explodes.

7 0
3 years ago
Other questions:
  • A carbon rod with a radius of 1.9 mm is used to make a resistor. What length of the carbon rod should be used to make a 3.7 Ω re
    6·1 answer
  • When an object absorbs light, what usually happens to its temperature?
    6·1 answer
  • Approximately how many kelvins are equal to 60°f? <br> a. 333 <br> b. 323 <br> c. 413 <br> d. 289
    7·2 answers
  • A distance between two consecutive troughs in a wave motion train produced in a string is 5 cm. Find speed of wave , if two comp
    12·1 answer
  • The object on the left is a discus, a piece of sports equipment made of a metal core, a plastic inner rim, and a metal outer rim
    14·1 answer
  • What is the name of the process that is responsible for the formation of elements heavier than hydrogen? A) fusion B) fission C)
    12·1 answer
  • What kind of destructive force or forces will most likely change the way Stone Mountain looks over the next million years? A) vo
    7·2 answers
  • whats ur funniest thing u have ever done in ur life mine was me sending a picture of me and my friend at the beach to my princip
    14·1 answer
  • 1. Four identical elephants are at different heights. If your physics teacher
    14·1 answer
  • A 200g ball is accelerated from 5m/s to 25m/s in 0.3sec. What force was applied?​
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!