Answer:
a = 4.96 m/s²
Explanation:
Given,
The mass of the box, m = 51 Kg
The magnitude of the applied force, Fₐ = 485 N
The friction force on the box, Fₓ = 232 N
The net force acting on the box is,
F = Fₐ - Fₓ
Substituting the given values in the above equation
F = 485 - 232
= 253 N
The acceleration of the crate is given by
a = F/m
= 253 / 51
= 4.96 m/s²
Hence, the acceleration of the crate is, a = 4.96 m/s²
Explanation:
Given that,
Initial speed of the rock, u = 30 m/s
The acceleration due to gravity at the surface of the moon is 1.62 m/s².
We need to find the time when the rock is ascending at a height of 180 m.
The rock is projected from the surface of the moon. The equation of motion in this case is given by :

It is a quadratic equation, after solving whose solution is given by:
t = 7.53 s
or
t = 8 seconds
(e)If it is decending, v = -20 m/s
Now t' is the time of descending. So,

Let h' is the height of the rock at this time. So,

or
h' = 155 m
Answer:
P V = N R T ideal gas equation
P2 / P1 = T2 / T1 where the other variables are constant
P2 = (T2 / T1) * P1 = (313 / 293) * 40 psi = 42.7 psi
True
False
True
My answers
B explanation : they are both filled to the same pint