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Zigmanuir [339]
3 years ago
15

B) Smartphone, iPad, and tablet are also a kind of computer.

Physics
1 answer:
valentinak56 [21]3 years ago
7 0

Answer:

Yes

Explanation:

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The distance between two successive maximaof
denpristay [2]

Answer:

v = 1.224 m/s

Explanation:

given,                          

distance between the two successive maxima = 1.70 m

number of crest = 8          

time = 11 s                            

frequency is equal to number of cycle per secod

f = \dfrac{8}{11}          

f = 0.72\ Hz                

velocity of wave

v = f x λ                

v = 0.72 x 1.70        

v = 1.224 m/s          

Hence, the wave speed is equal to v = 1.224 m/s

4 0
3 years ago
What is CHA-CHA-CHA.​
polet [3.4K]

Answer:

The cha-cha-cha, is a dance of Cuban origin. It is danced to the music of the same name introduced by Cuban composer and violinist Enrique Jorrin in the early 1950s. This rhythm was developed from the danzón-mambo

5 0
2 years ago
The pitch of a sound wave refers to the loudness of a wave. True False
Charra [1.4K]
False it refers to frequency
6 0
3 years ago
Read 2 more answers
The frequency of the given sound is 1.5khz then how many vibration it is completing in one second ?​
kompoz [17]

Answer:

1500 per second.

Explanation:

vibrations = 1.5 kilohertz

1.5×1000=1500

the answer is 1500 per second.

6 0
2 years ago
Read 2 more answers
The angle θ is slowly increased. Write an expression for the angle at which the block begins to move in terms of μs.
Reika [66]

Answer:

tan \theta = \mu_s

Explanation:

An object is at rest along a slope if the net force acting on it is zero. The equation of the forces along the direction parallel to the slope is:

mg sin \theta - \mu_s R =0 (1)

where

mg sin \theta is the component of the weight parallel to the slope, with m being the mass of the object, g the acceleration of gravity, \theta the angle of the slope

\mu_s R is the frictional force, with \mu_s being the coefficient of friction and R the normal reaction of the incline

The equation of the forces along the direction perpendicular to the slope is

R-mg cos \theta = 0

where

R is the normal reaction

mg cos \theta is the component of the weight perpendicular to the slope

Solving for R,

R=mg cos \theta

And substituting into (1)

mg sin \theta - \mu_s mg cos \theta = 0

Re-arranging the equation,

sin \theta = \mu_s cos \theta\\\rightarrow tan \theta = \mu_s

This the condition at which the equilibrium holds: when the tangent of the angle becomes larger than the value of \mu_s, the force of friction is no longer able to balance the component of the weight parallel to the slope, and so the object starts sliding down.

4 0
3 years ago
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