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2 years ago

Pleaseeee Please help, I will love you forever and ever

Physics

1 answer:

matrenka [14]2 years ago

6 0

Answer:

The answer to your question is

Explanation:

Data

mass = 0.5kg

T1 = 35

T2 = ?

Q = - 6.3 x 10⁴ J = - 63000 J

Cp = 4184 J / kg°C

Formula

Q = mCp(T2 - T1)

T2 = T1 + Q/mCp

Substitution

T2 = 35 - 63000/(0.5 x 4184)

T2 = 35 - 63000/2092

T2 = 35 - 30.1

T2 = 4.9 °C

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The detailed steps is as shown in the attached file

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2 years ago

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Answer:

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2 years ago

Mercury has a radial acceleration of 3.96 × 10−2 m/s2 and its orbital period is T = 88 days. What is the radius of Mercury’s orb

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Explanation:

Ok, the data we have is

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Where v is the velocity. r is the radius and w is the angular velocity.

And we know that:

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Then we can write:

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3 years ago

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ddd [48]

Answer:

The instantaneous speed of the object after the first five seconds is 12.5 m/s.

(C) is correct option.

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Given that,

An object starts at rest. Its acceleration over 30 seconds.

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We know that,

Area under the acceleration -time graph gives speed.

According to figure,

$speed = area\ of\ tringle$

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