The area of a rectangle is A=LW, the area of a square is A=S^2.
W=S-2 and L=2S-3
And we are told that the areas of each figure are the same.
S^2=LW, using L and W found above we have:
S^2=(2S-3)(S-2) perform indicated multiplication on right side
S^2=2S^2-4S-3S+6 combine like terms on right side
S^2=2S^2-7S+6 subtract S^2 from both sides
S^2-7S+6=0 factor:
S^2-S-6S+6=0
S(S-1)-6(S-1)=0
(S-6)(S-1)=0, since W=S-2, and W>0, S>2 so:
S=6 is the only valid value for S. Now we can find the dimensions of the rectangle...
W=S-2 and L=2S-3 given that S=6 in
W=4 in and L=9 in
So the width of the rectangle is 4 inches and the length of the rectangle is 9 inches.
Answer: a) P(x=0) = 0.0907, b) P(x≥10) = 0.7986
Step-by-step explanation: the probability mass function of a possion probability distribution is given as
P(x=r) = (e^-λ)×(λ^r) /r!
Where λ = fixed rate at which the event is occurring and each event is independent of each other = 2.4
a) P(x= at least one) = P(x≥1)
P(x≥1) = 1 - P(x<1)
But P(x<1) = P(x=0) { we can not continue to negative values because our values of x can only take positive values of integer}
Hence, P(x≥1) = 1 - P(x=0)
P(x=0) = e^-2.4 * 2.4^0/(0!)
P(x=0) = 0.0907×1/1
P(x=0) = 0.0907
b) if the average number of hits in 1 minutes is 2.4 then for 5 minutes we have 2.4×5 = 12.
Hence λ = 12.
P(x= at least 10) =P(x≥10) = 1 - P(x≤9)
P(x≤9) will be gotten using a cumulative possion probability distribution table whose area is to the left of the distribution.
From the table P(x≤9) = 0.2014.
P(x≥10) = 1 - 0.20140
P(x≥10) = 0.7986
=7(∛2x) - 6(∛2x) - 6(<span>∛x)
= </span>∛2x - 6<span>∛x
answer
C. </span>∛2x - 6∛x
third choice
Answer:
He won 6 games and lost 24 games.
The car will travel eighty miles in 1/2 hour
