A pet store has 11 puppies, including 2 poodles, 4 terriers, and 5 retrievers. If Rebecka and Aaron, in that order, each se
lect one puppy at random with replacement (they may both select the same one), find the probability that Rebecka selects a terrier and Aaron selects a retriever.
Since there are 14 puppies total and 5 of them are poodles, there 5 chances out of 14 for Rebecka to choose a poodle. Since the choices are done without replacement, there are now 13 left and 4 possibilities from which Aaron to choose. Since we want to calculate the probability that BOTH of them choose a poodle, we use the multiplication rule which tells us to multiply the individual probabilities.
The answer will be D. 7/10 because you have 10 numbers and you want to have a number greater than 3 so it would be 10-3=7 and 7 would go over 10 because there are 7 numbers greater than 3 but less than 10.