Question

A pet store has ​11 puppies, including ​2 poodles, 4 ​terriers, and 5 retrievers. If Rebecka and​ Aaron, in that​ order, each select one puppy at random with replacement​ (they may both select the same​ one), find the probability that Rebecka selects a terrier and Aaron selects a retriever.

Answer 1

Answer:

p=5/44

Step-by-step explanation:

According to the text, the selection is with replacement, so we always have the total number of pets in each selection:

$p=(\frac{4}{14} )(\frac{5}{14} )=\frac{20}{196} =\frac{10}{88} =\frac{5}{44}$

I hope this help you

Answer 2

Answer:  $10/91$

Step-by-step explanation:

Since there are 14 puppies total and 5 of them are poodles, there 5 chances out of 14 for Rebecka to choose a poodle. Since the choices are done without replacement, there are now 13 left and 4 possibilities from which Aaron to choose. Since we want to calculate the probability that BOTH of them choose a poodle, we use the multiplication rule which tells us to multiply the individual probabilities.

$(5/14)(4/13) = 10/91$