Ask question

Ask question

All categories

4 years ago

15

Your friend, who is age 15 and has a resting heart rate of 70, wishes to start a jogging program. What would you suggest as a pr

oper starting target heart rate?
138
115
178
155

2 answers:

Alex787 [66]4 years ago

6 0

I think the right answer for this question is : 138 because the boy is just 15 year old but he has resting heart rate of 70

garri49 [273]4 years ago

4 0

Actually its 155, got this wrong on my test when I put 138 :)

You might be interested in

A wheelbarrow can be used to help lift a load, such as a pile of dirt, and then push the load across a distance.

ELEN [110]

Answer:

a wheel and axle and a lever

5 0

3 years ago

Read 2 more answers

A 10-turn coil of wire having a diameter of 1.0 cm and a resistance of 0.50 Ω is in a 1.0 mT magnetic field, with the coil orien

n200080 [17]

Answer:

The voltage across the capacitor is 1.57 V.

Explanation:

Given that,

Number of turns = 10

Diameter = 1.0 cm

Resistance = 0.50 Ω

Capacitor = 1.0μ F

Magnetic field = 1.0 mT

We need to calculate the flux

Using formula of flux

$\phi=NBA$

Put the value into the formula

$\phi=10\times1.0\times10^{-3}\times\pi\times(0.5\times10^{-2})^2$

$\phi=7.85\times10^{-7}\ Tm^2$

We need to calculate the induced emf

Using formula of induced emf

$\epsilon=\dfrac{d\phi}{dt}$

Put the value into the formula

$\epsilon=\dfrac{7.85\times10^{-7}}{dt}$

Put the value of emf from ohm's law

$\epsilon =IR$

$IR=\dfrac{7.85\times10^{-7}}{dt}$

$Idt=\dfrac{7.85\times10^{-7}}{R}$

$Idt=\dfrac{7.85\times10^{-7}}{0.50}$

$Idt=0.00000157=1.57\times10^{-6}\ C$

We know that,

$Idt=dq$

$dq=1.57\times10^{-6}\ C$

We need to calculate the voltage across the capacitor

Using formula of charge

$dq=C dV$

$dV=\dfrac{dq}{C}$

Put the value into the formula

$dV=\dfrac{1.57\times10^{-6}}{1.0\times10^{-6}}$

$dV=1.57\ V$

Hence, The voltage across the capacitor is 1.57 V.

5 0

3 years ago

The mechanical force of contraction is generated by

maria [59]

it is generated by two objects pushing against each other with equal/almost equal force, therefore contracting against each other

4 0

3 years ago

all bearings are made by lebng spherical drops of molten metal fall inside a tall tower – called a shot tower – and solidify as

Wewaii [24]

Answer:

Part b)

h = 78.5 m

Part c)

v = 39.24 m/s

Explanation:

Part b)

If ball need t = 0 to t = 4 s then height of the tower is the total displacement of the ball in t = 4 s interval

here if ball start from rest

then its displacement is given as

$\Delta y = \frac{1}{2}gt^2$

$\Delta y = \frac{1}{2}(9.81)(4^2)$

$\Delta y = 78.5 m$

Part c)

Speed of the bearing at the end of the motion of the ball

$v_f = v_i + at$

$v_f = 0 + (9.81)(4)$

$v_f = 39.24 m/s$

7 0

3 years ago

Energy is unable to change forms. please select the best answer from the choices provided t f

allsm [11]

<span>Energy is unable to change forms. please select the best answer from the choices provided</span>

F - False

6 0

3 years ago

Read 2 more answers