Answer:
T= 38.38 N
Explanation:
Here
mass of can = m = 3 kg
g= 9.8 m/sec2
angle θ = 40°
From figure we see the vertical and horizontal component of tension force T
If the can is to slip - then horizontal component of tension force should become equal to force of friction.
First we find force of friction
Fs= μ R
where
μ = 0.76
R = weight of can = mg = 3 × 9.8 = 29.4 N
Now horizontal component of tension
Tx= T cos 40 = T× 0.7660 N
==>T× 0.7660 = 29.4
==> T= 38.38 N
Energy and Work have the same unit of measurement which is Joules in SI units.
Explanation:
- A Joule of Work is said to be done on an object when energy is transferred to that particular object.
- If two objects are involved, when one object transfers energy onto the second, a joule of work is said to be done by the first object.
- Work is also the application of force on an object over a distance. So Work = Force × Displacement
- Energy is neither created nor destroyed. It is in 2 forms - kinetic and potential.
- Kinetic energy is defined as the energy of a moving object while potential energy is known as the energy that is stored within an object.
- Kinetic Energy = 1/2 × mass × (velocity)²
- Potential Energy = mass × acceleration due to gravity × height
- Both energy and work are measured in Joules.
Beaker would be most appropriate for measuring the approximate volume of a liquid.
Answer:
The length of open-open pipe needed is 6.23 m
The length of open-close pipe needed is 3.11 m
Explanation:
Fundamental frequency for standing wave mode of an open- open pipe is given by
where v is the velocity and L is the length
The length of open-open pipe needed is
Fundamental frequency for standing wave mode of an open- close pipe is given by
The length of open-close pipe needed is
I actually believe for the first question, it would be complete destructive interference as the amplitude and the approximate wavelength for each are the same and will completely or entirely cancel out, rather than simply decreasing or lowering the amplitude as in the bottom question.
The amplitude for the first will be 0, as the 2 waves will cancel each other out. The amplitude of the second, will be 3x, I believe, assuming the amplitude of the first is 2x and the second is 1x, in a constructive interference, I believe the amplitudes would add up.
Likewise for the bottom, I believe you would be subtracting the supposed amplitude of the first which is 2x from 1x which would be 1x.
