All categories

4 years ago

Please help

2 answers:

8 0

I definitely agree with choise that you consider to be as a correct one. I am pretty sure that prganism is correct because this is a unit which ebrases all the mentioned points. And in simple words, the rest of options represent collective objects but you have to answer with sole one. Hope you find it helpful.

Rudik [331]4 years ago

4 0

Answer:

Yep totally C

Explanation:

You might be interested in

Sketch of the distance vs time graph for a car with constant velocity

kykrilka [37]

Answer:

It would look like the graph of y=x. A diagonal line starting at 0

7 0

3 years ago

A speed-time graph is shown below:

alexandr1967 [171]

Answer:

<em>The average acceleration of the object is 0.5 cm/s^2</em>. Answer: A)

Explanation:

<u>Average Acceleration</u>

The average acceleration of a moving object is the rate at which the speed changed over time in a specific period. It can be calculated as follows:

$\displaystyle \bar a=\frac{v_f-v_o}{t}$

Where vf is the final speed, vo is the initial speed and t is the time.

The speed-time shows the speed starts at 0 cm/s and ends at 4 cm/s over the 8 seconds period. The average acceleration is:

$\displaystyle \bar a=\frac{4-0}{8}=0.5$

The average acceleration is 0.5 cm/s^2

A) Correct. The average acceleration is 0.5 cm/s^2

B) Incorrect. The average acceleration is 0.5 cm/s^2

C) Incorrect. The average acceleration is 0.5 cm/s^2

D) Incorrect. The average acceleration is 0.5 cm/s^2

3 0

3 years ago

In a closed system with no friction, a red sphere of 2.5 kg stands stationary. A blue sphere with a mass of 5.8 kg approaches th

Ipatiy [6.2K]

Answer:

m1 = the mass of the blue sphere = 5.8 kg

m2 = the mass of the red sphere = 2.5 kg

v1 = initial velocity of the blue sphere before the collision = 4.1 m/s

v2 = initial velocity of the red sphere before the collision = 0 m/s

v'1 = final velocity of the blue sphere after the collision = 1.3 m/s

v'2 = final velocity of the red sphere after the collision = ?

using conservation of momentum

m1v1 + m2v2 = m1v'1 + m2v'2

(5.8) (4.1) + (2.5) (0) = (5.8) (1.3) + (2.5) (v'2)

23.78 = 7.54 + (2.5) (v'2)

-7.54 -7.54

16.24 = (2.5) v'2

--------- -----------

2.5 2.5

v'2 = 6.5

Explanation:

5 0

3 years ago

Rocks that are formed as a result of deposits from weathering and erosion

zimovet [89]

<h2>Answer: Sedimentary rocks </h2>

Sedimentary rocks are formed from sediments and deposits of particles of various types, forms and sizes that are transported by air, wind or water, and then subjected to chemical processes to become rocks.

These types of rocks are usually found in the form of layers or strata in places where sediment accumulates due to the erosion of other materials, for example on the banks of rivers, in valleys, lakes (and any other type of body of water).

8 0

3 years ago

You are driving due north on i-81 to come to jmu with a speed of 10 m/s, suddenly you realize you forgot your book. You make a u

Readme [11.4K]

first we make a U turn and travel towards home in t = 20 s

so the distance of home from initial position is

$d_1 = v*t_1$