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notka56 [123]
3 years ago
15

- 4. What is the roster form of the set K = {x/x are odd numbers from 2 to 8} ? A. H = {2, 4, 6, 8} C. H = {3, 4, 5, 6, 7} B. H

= {3, 5, 7} D. H = {2,8} 1 2 3 ? Which method for theiva CIV & CLUJ -​
Mathematics
1 answer:
tangare [24]3 years ago
3 0
<h3>Answer:  H = {3, 5, 7}</h3>

Explanation:

We simply list any odd number that is between 2 and 8. The term "roster form" can be thought of as listing the roster of a sports team (eg: baseball). So instead of describing what the numbers look like, we list out the numbers themselves. Those numbers being 3, 5 and 7.

Something like {2,4,6,8} is ruled out because we're dealing with odd numbers only.

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Combine like terms - 7 -3(4-2x)-10x
Shtirlitz [24]

Answer:

The simplified form would ve -19 - 4x

Step-by-step explanation:

Before we combine anything, we first must expand the expression by distributing the -3 to the terms in the parenthesis.

-7 - 3(4 - 2x) - 10x

-7 - 12 + 6x - 10x

Now we can combine the terms with and without variables.

-19 - 4x

8 0
3 years ago
Read 2 more answers
25 points
lbvjy [14]

Answer:

unit_4_study_guide_solutions.pdf

Step-by-step explanation:

This link is a study guide, and on the LAST PAGE it has the answer to your question!

4 0
3 years ago
One of the tallest buildings in a country is topped by a high antenna. The angle of elevation from the position of a surveyor on
irina1246 [14]

Answer:

a. distance of the surveyor to the base of the building = 2051.90 ft

b. height of the building = 1384 ft

c. Angle of elevation from the surveyor to the top of the antenna = 38.31°

d. Height of antenna  =  237.08 ft

Step-by-step explanation:

​The picture above is a illustration of the described event.

a = the height of the flag

b = the height of the building

c = distance of the surveyor from the base of the building

the angle of elevation from the position of the surveyor on the ground to the top of the building = 34°  

distance from her position to the top of the building  = 2475 ft

distance from her position to the top of the flag  = 2615 ft

​(a) How far away from the base of the building is the surveyor​ located?​

using the SOHCAHTOA principle

cos 34° = c/2475

c =  0.8290375726  × 2475

c = 2051.8679921

c = 2051.90 ft

(b) How tall is the​ building

The height of the building = b

sin 34° = opposite /hypotenuse

0.5591929035 = b/2475

b =  0.5591929035  × 2475

b =  1384.0024361

b =  1384.00 ft

​(c) What is the angle of elevation from the surveyor to the top of the​ antenna?

let the angle = ∅

cos ∅ = adjacent/hypotenuse

cos ∅ = 2051.90/2615

cos ∅ =  0.784665392

∅ = cos-1  0.784665392

∅ =   38.310258303

∅ =  38.31°

​(d) How tall is the​ antenna?

height of the antenna = a

sin 38.31° = opposite/hypotenuse

sin 38.31° = (a + b)/2615

sin 38.31° × 2615 = (a + b)

(a + b) =  0.6199159917  × 2615

(a + b) =  1621.0803182

(a + b) = 1621. 08 ft

Height of antenna = 1621. 08 - 1384.00  =  237.08031822 ft

Height of antenna  =  237.08 ft

8 0
3 years ago
Find mABC<br><br> A-54<br> B-135<br> C-15<br> D-126
bagirrra123 [75]
It’s B



Glad I could help
7 0
3 years ago
5) HELP I don't know what I got incorrect can you please give me the answer and the step by step, THANK YOU SO MUCH TYSM!!!
MariettaO [177]
Same as moren.. sorry
6 0
3 years ago
Read 2 more answers
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