Answer:
The statement BI = BK is true from the given information ⇒ B
Step-by-step explanation:
If a line is a perpendicular bisector of a line segment, then
- The line intersects the line segment in 4 right angles
- The line intersects the line segment in the mid-point of the line segment
- Any point on the line is equidistant from the endpoints of the line segment
Let us find the true statement
∵ Line AB is the perpendicular bisector of segment IK
→ By using the 1st note above
∴ AB ⊥ IK
∴ ∠IJA, ∠KJA, ∠IJB, ∠KJB are right angles
→ By using the 2nd note above
∴ J is the mid-point of IK
∴ IJ = JK
∵ Any point on line AB is equidistant from The endpoints of IK ⇒ 3rd note
∴ AI = AK
∴ BI = BK
∴ The statement BI = BK is true from the given information
12x1= 12
12+ 11= 23
23/12 + 9/12 = 32/12 or 3 8/12
Answer: I'm not sure if this is right or not but I got U = 4
Step-by-step explanation: -8(2v-2)=-4(7+5u. So first I distributed and got -16v -16 = 28 + 20u. And then I added 16u with 20u I added because you change the sign like if it's a negative you make it a positive so once you do 20u+16v you should get 36 and then on the other side it should be -16+16 which equals -16u from when you distributed so now you should have -16u=28+36 so now you would add 28 the 36 since they both are positives and have no variables which you should get 64 and then on the left you should have 16u. So it looks like -16u=64. And then now you would divide -16u on both sides and the side with the variable put it or v whatever variable you want to use and then do 64 divided by 16 and you should get 4.
Kaden 12
izaih 8
kaden gives 8
12-8
answer 4
0 and 2
f(x) = g(x) will be the input or x value at which f and g have the same output or y value. Look in the table where two numbers repeat right next to each other.
−1 −7/2 −9/2
0 −3 −3
1 −2 −3/2
2 0 0
3 4 3/2
4 12 3
5 28 9/2
There are two solutions to f(x) = g(x) which are x=0 and x=2.
