Answer:
240 houses
Step-by-step explanation:
Given that:
Number of streets = 4
Length of each street = 3/4 miles long
Street is divided into lots with one house built per lot
1 mile = 5289 feets
3/4 miles = (3/4) * 5280 = 3960 feets
Hence, street is 3960 feets long
Since each lot must have at least 65 feet frontage along the street:
Number of lots per street :
Length of street / frontage length
3960 ft / 65 ft = 60.92
Hence, maximum number of lots per street = 60 lots per street
Maximum number of houses in New neighborhoods :
Number of lots per street × number of streets
= 60 × 4
= 240 houses
Before:It's too short. Write at least 20 characters to explain it well.
After:It's too short. Write at least 20 characters to explain it well.
<h2>
Maximum area is 25 m²</h2>
Explanation:
Let L be the length and W be the width.
Aidan has 20 ft of fence with which to build a rectangular dog run.
Fencing = 2L + 2W = 20 ft
L + W = 10
W = 10 - L
We need to find what is the largest area that can be enclosed.
Area = Length x Width
A = LW
A = L x (10-L) = 10 L - L²
For maximum area differential is zero
So we have
dA = 0
10 - 2 L = 0
L = 5 m
W = 10 - 5 = 5 m
Area = 5 x 5 = 25 m²
Maximum area is 25 m²
