(a) Determine the circumference of the Earth through the equation,
C = 2πr
Substituting the known values,
C = 2π(1.50 x 10¹¹ m)
C = 9.424 x 10¹¹ m
Then, divide the answer by time which is given to a year which is equal to 31536000 s.
orbital speed = (9.424 x 10¹¹ m)/31536000 s
orbital speed = 29883.307 m/s
Hence, the orbital speed of the Earth is ~29883.307 m/s.
(b) The mass of the sun is ~1.9891 x 10³⁰ kg.
Answer:
Explanation:
Distance of each of the charges from the center are equal . If this distance be d
d = .5 x length of diagonal of square
length of diagonal = 4√2
d = .5 x 4√2
= 2√2
potential at a point
V = k Q / r where k is a constant , Q is charge and r is distance of the point from the charge .
k = 9 x 10⁹
Total potential = 
= 
= 9 √2 x 10⁹ V .
Answer:
The neutrinos are produced in the core of the sun by nuclear fusion and measuring their number helps us confirm that there are enough proton-proton chain reactions of each which produce a neutrino and going on in the Sun's core to explain the energy output of the Sun.
Answer:
if it is at a speed of 12.5 m / s it would take 2 minutes
Explanation:
Distance = speed* time
10x10^-3 *u + 10x10^-3 * 2u = 125
0.01u + 0.02u = 125
0.03u = 125
u = 4166.66666.... s
acceleration = (final velocity - initial velocity)/time
(10x10-3 - 0)/4167 = 2.3998 * 10^-6 m s-2
