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Usimov [2.4K]
4 years ago
13

The earth travels around the sun once a year in an approximately circular orbit whose radius is 1.50x10^11 m. From this data det

ermine (a) the orbital speed of the earth and (b) the mass of the sun.
Physics
1 answer:
seraphim [82]4 years ago
8 0
(a) Determine the circumference of the Earth through the equation,
            C = 2πr
Substituting the known values, 
           C = 2π(1.50 x 10¹¹ m)
             C = 9.424 x 10¹¹ m

Then, divide the answer by time which is given to a year which is equal to 31536000 s. 
          orbital speed = (9.424 x 10¹¹ m)/31536000 s

               orbital speed = 29883.307 m/s

Hence, the orbital speed of the Earth is ~29883.307 m/s.

(b) The mass of the sun is ~1.9891 x 10³⁰ kg. 
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{\huge{\fcolorbox{yellow}{red}{\orange{\boxed{\boxed{\boxed{\boxed{\underbrace{\overbrace{\mathfrak{\pink{\fcolorbox{green}{blue}{Answer}}}}}}}}}}}}}

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\textsf{By using Charles's law}  \\  \\  \tt{ \frac{V_1}{T_1}  =  \frac{V_2}{T_2} }

\sf Now \: sustituting \: the \: values

\sf  \longmapsto \frac{0.5}{293.15}  =  \frac{V_2}{423.15}  \\  \\  \\  \sf \longmapsto  \frac{0.5 \times 423.15}{293.15}  = V_2 \\  \\  \\  \sf  \longmapsto  \frac{211.575}{293.15}  = V_2 \\  \\  \\  \boxed {\longmapsto 0.72l = V_2}

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