The earth travels around the sun once a year in an approximately circular orbit whose radius is 1.50x10^11 m. From this data det
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Answer:
The magnitude of the gravitational field strength near Earth's surface is represented by approximately .
Explanation:
Let be M and m the masses of the planet and a person standing on the surface of the planet, so that M >> m. The attraction force between the planet and the person is represented by the Newton's Law of Gravitation:
Where:
- Mass of the planet Earth, measured in kilograms.
- Mass of the person, measured in kilograms.
- Radius of the Earth, measured in meters.
- Gravitational constant, measured in
.
But also, the magnitude of the gravitational field is given by the definition of weight, that is:
Where:
- Mass of the person, measured in kilograms.
- Gravity constant, measured in meters per square second.
After comparing this expression with the first one, the following equivalence is found:
Given that ,
and
, the magnitude of the gravitational field near Earth's surface is:
The magnitude of the gravitational field strength near Earth's surface is represented by approximately .