Answer:
The correct answer is from solid to liquid (melting), and from liquid to gas (sublimation).
Explanation:
In the solid-state the energy of the molecules is low, so the molecules will have very little movement. In the liquid state, molecules have a higher level of energy, and as they move from solid to liquid state they acquire greater mobility. In a gaseous state, the energy level is very high and the molecules have a higher degree of mobility.
This can also be described through the predominant molecular forces in each state. The cohesion forces present in solids are stronger than those of repulsion. In the liquid state, the repulsion and attraction forces are balanced. Finally, in the gaseous state, the repulsive forces between the molecules predominate.
Have a nice day!
( 8.10) x 10^4 J = ½(1010kg)V²
<span>......................= 505V² </span>
<span>( 8.10) x 10^4 J =[(.0505) x 10^4] V² ........<==10^4 cancels </span>
<span>8.10 = .0505 V² </span>
<span>.........______ </span>
<span>V = ²√ 160.4 </span>
<span>V= 12.6 m/s </span>
<span>(that's 12.6m/sec(1km/1000m)(3600secs/1hr) = 45.36kph) </span>
<span> my diagram is wrong, it is just an ordinary car, </span>
The reading on the scale is greater than your actual weight.
Answer:
Thin, aluminium and buried underground.
Explanation:
When it comes to electrification of a state or province, some characteristics of the wire to use must be considered. This would help to minimize and avoid power loss and wire burns.
i. The wire to use should be thin, and a quite number can be twisted one against the other so as to increase the surface area for heat dissipation.
ii. Aluminium wire is more preferable for this project. It has a high melting point, and reduces energy loss.
iii. Burying the wire underground through an insulator is the best choice, though expensive but would preserve the wire from external influence.
Energy is (transferred) when it is moved from one obect to another.
The answer is (b)
