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OLga [1]
3 years ago
12

Two trains are traveling side-by-side along parallel, straight tracks at the same speed. In a time t, train A doubles its speed.

In the same time train B increases its speed by a factor of 5.42. By what factor is the distance traveled by train B in time t greater than the distance traveled by train A in the same time t?
Physics
1 answer:
sergij07 [2.7K]3 years ago
3 0

Answer:

derdddrdickdd

Explanation:

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Answer: C.

Explanation:

For a parallel-plate capacitor where the distance between the plates is d.

The capacitance is:

C = e*A/d

You can see that the distance is in the denominator, then if we double the distance, the capacitance halves.

Now, the stored energy can be written as:

E = (1/2)*Q^2/C

Now you can see that in this case, the capacitance is in the denominator, then we can rewrite this as:

E = (1/2)*Q^2*d/(e*A)

e is a constant, A is the area of the plates, that is also constant, and Q is the charge, that can not change because the capacitor is disconnected.

Then we can define:

K = (1/2)*Q^2/(e*A)

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E = K*d

Then the energy is proportional to the distance between the plates, this means that if we double the distance, we also double the energy.

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What are parts of<br> chromosomes.<br> Momcomes are made of
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Explanation:

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A car traveling at 26 m/s starts to decelerate steadily. It comes to a complete stop in 13 seconds. What is its acceleration?
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A soccer ball kicked with a force of 12.5 N accelerates at 6.2 m/s’ to the right. What is the mass of the ball? Answer in units
stepladder [879]

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