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lesya692 [45]
3 years ago
14

Dearden Corporation uses a job-order costing system with a single plantwide predetermined overhead rate based on machine-hours.

The company based its predetermined overhead rate for the current year on total fixed manufacturing overhead cost of $144,000, variable manufacturing overhead of $2.00 per machine-hour, and 60,000 machine-hours. The predetermined overhead rate is closest to:
Mathematics
1 answer:
Blababa [14]3 years ago
6 0

Answer:

23

Step-by-step explanation:

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A merchant wants to establish the selling price of an item that costs him $4.50 with a 15% markup. What is his selling price?
OLga [1]

Answer:

the answer it $5.18

Step-by-step explanation:

$4.50 + ($4.50 x .15)

$4.50 + $0.68 = $5.18

4 0
3 years ago
The Frostburg-Truth bus travels on a straight road from Frostburg Mall to Sojourner Truth Park. The mall is 3 miles west and 2 m
Verizon [17]
To start, write your locations as points, with north and south being positive and negative y respectively and east and west being positive and negative x respectively. Doing this gives us the mall at (-3,-2) and the park at (4,5). Now, we use our distance formula ( \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 } ) to solve for the unknown distance. Plugging in with the park values as our second values and our mall values as our first values (as well as with our unknown distance as d), we get d= \sqrt{(4-(-3))^2+(5-(-2))^2} = \sqrt{(7)^2+(7)^2} = \sqrt{49+49} = \sqrt{98}. This square root can be rounded to 9.9 miles.
4 0
3 years ago
HELP!!! NEED HELP!!!!
blsea [12.9K]

Answer:

C

Step-by-step explanation:

6 0
3 years ago
Use an online to to estimate the cost for one year at a 4 year university and one year at a 2 year college in Texas.
mart [117]
The answer is 50’ because the majority of the population is very high in Europe
6 0
3 years ago
Suppose you solved a second-order equation by rewriting it as a system and found two scalar solutions: y = e^5x and z = e^2x. Th
xenn [34]

Answer:

The solutions are linearly independent because the Wronskian is not equal to 0 for all x.

The value of the Wronskian is \bold{W=-3e^{7x}}

Step-by-step explanation:

We can calculate the Wronskian using the fundamental solutions that we are provided and their corresponding the derivatives, since the Wroskian is defined as the following determinant.

W = \left|\begin{array}{cc}y&z\\y'&z'\end{array}\right|

Thus replacing the functions of the exercise we get:

W = \left|\begin{array}{cc}e^{5x}&e^{2x}\\5e^{5x}&2e^{2x}\end{array}\right|

Working with the determinant we get

W = 2e^{7x}-5e^{7x}\\W=-3e^{7x}

Thus we have found that the Wronskian is not 0, so the solutions are linearly independent.

3 0
3 years ago
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