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2 years ago

I need answers fast please help is you know answer!!!!

Mathematics

1 answer:

Rasek [7]2 years ago

4 0

Answer:

baap se jakar puch madarchod!!!!

please translate it in g••gle...

thanks......

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Shane said that he could write related multiplication and addition sentences for 6+4+3. Does Shanes statement make sense?

stich3 [128]

No his answer does not make sense

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3 years ago

Through: (-3,2) and (0, -3)

abruzzese [7]

Answer:

y = -5/3x - 3

Assuming this is a linear function

Step-by-step explanation:

1. Use (y2-y1)/(x2-x1) to find the slope of the equation, assuming it is a linear function.

(-3-2)/(0+3) = -5/3 <--- slope

2. The y-intercept is going to be the (0, -3) point, since the point is directly on the y-axis.

3. Put both of those values into the new equation

y = -5/3x - 3

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3 years ago

What are the two ordered pairs for 5x=3

valkas [14]

Well the equation of this line is $x=3/5$ . Which means that for any value of y the x will always equal to 3/5, so the points (ordered pairs) for eg. are $(3/5,2),(3/5,\sqrt{7})$ .

Hope this helps.

3 0

3 years ago

What the answer now

stiks02 [169]

Answer:

35.6 yd²

Step-by-step explanation:

Area of ∆UVW can be solved if we know the lengths of 2 sides and their included angle.

We are Given just 1 side, UV (w). Use the law of sines to find UW (v).

Thus:

$\frac{v}{sin(V)} = \frac{w}{sin(W)}$

W = 137°

w = 19 yd

V = 180 - (137 + 22) = 21° => sum of triangle

v = ??

Plug in the values and solve for v

$\frac{v}{sin(21)} = \frac{19}{sin(137)}$

Multiply both sides by sin(21)

$\frac{v}{sin(21)}*sin(21) = \frac{19}{sin(137)}*sin(21)$

$v = \frac{19*sin(21)}{sin(137)}$

$v = 10 yd$ (approximated)

Find area of ∆UVW:

Area = ½*UV*UW*sin(U)

Area = ½*v*w*sin(U)

= ½*10*19*sin(22)

Area = 35.6 yd² (to nearest tenth)

7 0

3 years ago

Find the measure of arc DB.

mafiozo [28]

ñ!

$.30261 {23680x}^{?}$

4 0

3 years ago