Answer: 3.54
Explanation:
You're forgetting to divide by 3 for the 3 moles of potassium that are in potassium phosphate.
Potassium Phosphate= K3PO4
Answer:
ΔH°rxn = -827.5 kJ
Explanation:
Let's consider the following balanced equation.
2 PbS(s) + 3 O₂(g) → 2 PbO(s) + 2 SO₂(g)
We can calculate the standard enthalpy of reaction (ΔH°rxn) from the standard enthalpies of formation (ΔH°f) using the following expression.
ΔH°rxn = [2 mol × ΔH°f(PbO(s)) + 2 mol × ΔH°f(SO₂(g)
)] - [2 mol × ΔH°f(PbS(s)) + 3 mol × ΔH°f(O₂(g)
)]
ΔH°rxn = [2 mol × ΔH°f(PbO(s)) + 2 mol × ΔH°f(SO₂(g)
)] - [2 mol × ΔH°f(PbS(s)) + 3 mol × ΔH°f(O₂(g)
)]
ΔH°rxn = [2 mol × (-217.32 kJ/mol) + 2 mol × (-296.83)] - [2 mol × (-100.4) + 3 mol × 0 kJ/mol]
ΔH°rxn = -827.5 kJ
Explanation:
The given reaction is as follows.
Hence, number of moles of NaOH are as follows.
n = 
= 0.005 mol
After the addition of 25 ml of base, the pH of a solution is 3.62. Hence, moles of NaOH is 25 ml base are as follows.
n = 
= 0.0025 mol
According to ICE table,
Initial: 0.005 mol 0.0025 mol 0 0
Change: -0.0025 mol -0.0025 mol +0.0025 mol
Equibm: 0.0025 mol 0 0.0025 mol
Hence, concentrations of HA and NaA are calculated as follows.
[HA] = 
[NaA] =
![[A^{-}] = [NaA] = \frac{0.0025 mol}{V}](https://tex.z-dn.net/?f=%5BA%5E%7B-%7D%5D%20%3D%20%5BNaA%5D%20%3D%20%5Cfrac%7B0.0025%20mol%7D%7BV%7D)
Now, we will calculate the 
value as follows.
pH = 
![pK_{a} = pH - log \frac{[A^{-}]}{[HA]}](https://tex.z-dn.net/?f=pK_%7Ba%7D%20%3D%20pH%20-%20log%20%5Cfrac%7B%5BA%5E%7B-%7D%5D%7D%7B%5BHA%5D%7D)
= 
= 3.42
Thus, we can conclude that of the weak acid is 3.42.
Answer:
4 C3H5N3O9 ------> 6N2 + O2 + 10H2O + 12CO2
Explanation:
Nitroglycerin has a chemical formula C3H5N3O9. The balanced chemical equation is as follows:
4 C3H5N3O9 ------> 6N2 + O2 + 10H2O + 12CO2
We suppose that in a reaction, 44g of carbon dioxide is produced. The mass of nitroglycerin that must have reacted will be calculated as under:
Molecular mass of Nitroglycerin = 227g/mol
Molecular mass of Carbon dioxide = 44g/mol
No. of moles of carbon dioxide produced = 44/44 = 1 mole produced.
Now, from balanced chemical equation, we can see that
12 moles of carbon dioxide are produced by = 4 moles of nitroglycerin.
1 mole of carbon dioxide is produced by = 4/12 = 1/3 moles of nitroglycerin.
Mass of nitroglycerin which produced 1 mole of carbon dioxide = 1/3 x 227 = 75.666 grams.
Hi!
When titrating Calcium and Water solution, if there is some CaCO3 in the solution, the following reactions may occur in acid solution:
CaCO₃ + H⁺ → Ca⁺² + HCO₃⁻
HCO₃⁻ + H⁺ ↔ H₂CO₃ → CO₂ (g) + H₂O
The bubbles are from CO₂ that is being developed from an acidic solution of CaCO₃
