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egoroff_w [7]
3 years ago
7

An electron confined in a one-dimensional box is observed, at different times, to have energies of 12 eV, 27 eV, and 48 eV. What

is the length of the box? 45. | The nucleus of a typical atom
Chemistry
1 answer:
Fynjy0 [20]3 years ago
8 0

Answer:

l=3.5*10^{-10}m

Explanation:

From the question we are told that:

1st Energy     E_1=12eV=4(3eV)

2nd Energy  E_2=27eV=9(3eV)

3rd Energy   E_3=48eV=16(3eV)

 

Generally the equation for Energy E for electron in one dimensional box at ground state E_0 is mathematically given by

  E_0=\frac{h}{8ml^2}

  E_0=\frac{h}{8ml^2}

Therefore Length a is mathematically given as

l=\sqrt{\frac{h^2}{8mE_0} }

l=\sqrt{\frac{(6.625*10^{-34})^2}{8(9.1*19^{-31}{(3eV(1.6*10^{-19}))}}

l=3.5*10^{-10}m

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Answer:

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Explanation:

Let's combine the Ideal Gases Law with density to get the molecular formula for the unknown gas.

Density = mass / volume

1.06 g /L means that 1.06 grams of compound occupy 1 liter of volume.

P . V = n . R . T

Pressure in Torr must be converted to atm

760 Torr are 1 atm

371 Torr  are __ (371 .1)/760 = 0.488 atm

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(0.488 atm . 1L) / 0.082 . 304K = 1.06g/ MM

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0.0195 mol = 1.06g / MM

1.06g/0.0195 mol = MM →  54.3 g/m

Now, let's use the composition

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48 g of C are included un 4 atoms

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What is the pH if the [H+] concentration is 3 x10^-13​
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Explanation:

Given that,

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We know that, the definition of pH is as follows :

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Put all the values,

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So, the pH is 12.52.

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