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2 years ago

The number of moles and the mass of carbon dioxide formed by the combustion of 20.0 kg of carbon in an excess of oxygen.

1 answer:

8 0

The number of mole and mass of carbon dioxide produced by the combustion of 20.0 kg of carbon in an excess of oxygen are:

1. The number of mole of CO₂ produced is 1666.67 moles

2. The mass of CO₂ produced is 73333.48 g

We'll begin by calculating the number of mole in 20 Kg of carbon. This can be obtained as follow:

Mass of C = 20 Kg = 20 × 1000 = 20000 g

Molar mass of C = 12 g/mol

Mole = mass /molar mass

Mole of C = 20000 / 12

<h3>Mole of C = 1666.67 moles</h3>

1. Determination of the number of mole of CO₂ produced.

C + O₂ —> CO₂

From the balanced equation above,

1 mole of C reacted to produce 1 mole of CO₂.

Therefore,

1666.67 moles of C will also react to produce 1666.67 moles of CO₂.

Thus, 1666.67 moles of CO₂ were obtained from the reaction.

2. Determination of the mass of CO₂ produced.

Mole of CO₂ = 1666.67 moles

Molar mass of CO₂ = 12 + (16×2) = 44 g/mol

Mass = mole × molar mass

Mass of CO₂ = 1666.67 × 44

Thus, the mass of CO₂ produced from the reaction is 73333.48 g

Learn more: brainly.com/question/22387155

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3 years ago

Which of these is a chemical property? color, compressibility, heat of combustion, malleability

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3 years ago

Read 2 more answers

opper(I) ions in aqueous solution react with NH 3 ( aq ) according to Cu + ( aq ) + 2 NH 3 ( aq ) ⟶ Cu ( NH 3 ) + 2 ( aq ) K f =

Y_Kistochka [10]

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Explanation:

The dissolved amount of sparingly soluble salts is interlinked with a unitlesss quantity called as solubility product. It is a fixed quantity that only increases with the rise in temperatures and is used to predict the salting out of compounds. If the value of ionic product (Q) is larger than (Ksp), precipitation of compound occurs.

Given:

The solubility product of CuBr is 6.3×10−9.

The concentration of NH3 is 0.10 M.

Formula and Calculations:

The dissolution reaction (I) of CuBr is shown below.

The reaction showing dissolution of CuBr in NH3 is shown below.

The above reaction can be obtained by adding reaction (I) and (II) as shown below.

The equilibrium constants will get multiplied.

Suppose the solubility of CuBr is “s”.

It is given that concentration of NH3 is 0.10 M.

The equilibrium constant expression for the above reaction is as follows,

Here,

The concentration of pure solids is 1 M. Thus, the concentration of CuBr is 1 M.

As calculated, the value of Ksp is 396.9.

Substitute all the required values in above formula.

On further solving above equation,

Therefore, the solubility of CuBr in ammonia is 0.386 M.

The formula to calculate solubility

Solubuility (g/l)= Molarity(M) x Molarmass

Chemistry homework question answer, step 2, image 10

The molar mass of CuBr is 143.45 g/mol.

The formula to calculate solubility in g/L is given below.

The molar mass of CuBr is 143.45 g/mol.

therefore,

solubility = 0.386M x 143.45g/mol

where (M = mol/l)

solubility = 55.375g/l

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3 years ago

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3 years ago

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nordsb [41]

<u>Answer:</u> The chemical equations are written below.

<u>Explanation:</u>

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The chemical equation for the combustion of methane follows:

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This is also an example of combustion reaction.

The chemical equation for the combustion of butane follows:

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When an acid reacts with a base, it leads to the formation of salt and water. This reaction is known as neutralization reaction

The chemical equation for the reaction of potassium hydroxide and sulfuric acid follows:

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4 years ago