<span>Missing question: The first-order rate
constant for the decomposition of N2O5, 2N2O5(g)→4NO2(g) + O2(g) at 70°</span><span>C is 6.82×10−3 s−1. Suppose we start with 2.70×10−2 mol of
N2O5(g) in a volume of 1.8 L . </span>c₀(N₂O₅) = 0,027 mol ÷ 1,8 L.<span>
c</span>₀(N₂O₅) =
0,015 mol/L.<span>
c(N</span>₂O₅) = 0,019 mol/ 1,8 L = 0,01055 mol/L.<span>
k = 6,82·10</span>⁻³ s⁻¹.<span>
ln c(N</span>₂O₅) =
ln c₀(N₂O₅) -
k·t.<span>
t = (ln c</span>₀(N₂O₅) - ln c(N₂O₅)) ÷ k.<span>
t = 0,35 ÷ 0,00682 s</span>⁻¹.<span>
t = 51 s = 0,86 min.</span>
