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2 years ago

Fill in the blanks of the statement, using <, >, or = I

Mathematics

1 answer:

GarryVolchara [31]2 years ago

3 0

$\huge\underline\mathtt\colorbox{cyan}{=}$

$\huge\bold{\purple{\bold{⚡Because⚡}}}$

|-100|= positive 100

|-100|=100

$\huge\mathsf\colorbox{white}{}$

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You ask 125 randomly chosen students to name their favorite food. There are 1500 students in the school. Predict the number of s

jasenka [17]

1500-125=1,375
so 1375 should be your answer.

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3 years ago

To play the lottery in a certain state, a person has to correctly select 5 out of 45 numbers, paying a $1 for each five-number s

defon

There are 45 numbers out of which 5 numbers are required to win an enormous sum of money

No of ways in which 5 numbers can be selected out of 45 numbers.

$C_{45}^5=\frac{45!}{40!5!} =1221759$

out of which there is only combination foe contest winning

$P=\frac{1}{1221759}$

When 100 different tickets are bought then

Probability of winning: $\frac{100}{1221759}$

Probably of winning≈0,000082

/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\

P.S. Hello from Russia :^)

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3 years ago

Help me 20 POINTS MATH

madreJ [45]

Answer: D

Step-by-step explanation: ITS THE ONLY ONE THAT MAKES SENSE.

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3 years ago

Read 2 more answers

Nonlinear Systems of Equations

zheka24 [161]

The square root and cube root identities are proved.

According to the statement

we have to find that the use of the square root identity (x − y)2 = x2 − 2xy + y2

And use of cube root identity a3 + b3 = (a + b)(a2 − ab + b2).

So, For this purpose, we know that the

A. Let us assume the two conditions.

So,

2x + 3y = 6 -(1)

4x + 7y = 8 -(2)

Here we use elimination method

So, Multiply 4 with (1) and 2 with (2)

8x + 12y = 24

8x + 14y = 16

Now eliminate x from these equations

-2y = 8

here y is -4.

and the x become

2x + 3y = 6

2x -12 = 6

2x = 18

x = 9.

B. For the use of identity $(x- y)^{2} = x^{2} - 2xy + y^{2}$

Let us assume a number 26 and 28 then fill it in the condition then

$(28- 26)^{2} = 28^{2} - 2(28)(26) + 26^{2}$

Then

$(28- 26)^{2} = 784 - 1456 + 676$

$(28- 26)^{2} = 4$

And we have to prove the cube root identity then

The identity is

$a^{3} + b^{3} = (a + b)(a^{2} - ab + b^{2})$

Then let us assume the number 8 and 9 then

$a^{3} + b^{3} = (a + b)(a^{2} - ab + b^{2})$

$8^{3} + 9^{3} = (8 + 9)(8^{2} - 8*9 + 9^{2})$

$8^{3} + 9^{3} = (17)(64 - 72 + 81)$

$8^{3} + 9^{3} = (17)(73)$

$8^{3} + 9^{3} = (1241)$

Hence by this way we prove the square and cube root identities.

So, The square root and cube root identities are proved.

Learn more about square root and cube root here

brainly.com/question/661780

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3 0

1 year ago

18 is ______percent of 40

user100 [1]

Answer:

18 is 45% of 40

Step-by-step explanation:

3 0

2 years ago