5) A positive plus a negative will (always, sometimes, never) be negative.

Mathematics

1 answer:

GREYUIT [131]2 years ago

5 0

Hello logan693616!

$\huge \boxed{\mathbb{QUESTION} \downarrow}$

A positive plus a negative will (always, sometimes, never) be negative.

Give an example that proves your answer:

$\large \boxed{\mathbb{ANSWER\: WITH\: EXPLANATION} \downarrow}$

A positive plus a negative will sometimes be negative.

Suppose, we take a positive number whose value is greater than that of the negative number. While adding them, we'll take the sign of the greater number, which in this case is positive, so our answer will be a positive number. For example, +4 + (-3) = +1.
Now, if we take a negative number which is greater than the positive number, the sum of the two numbers will be negative. For example, (-4) + 3 = -1.
So, the answer can actually depend based on the value of the numbers used.
Hence, our answer is ⇨ A positive plus a negative will sometimes be negative.

__________________

Hope it'll help you!

ℓu¢αzz ッ

You might be interested in

Elaine is taking a test that has multiple choice questions,each with 4 answer choices. She comes to a question for which she doe

jekas [21]

Assuming There is ONLY ONE CORRECT ANSWER,

The probability of her guessing the answer without ruling out the choices is 1/5.

if 3 choices are ruled out, then 1 out of the remaining two is right, which gives the probability 1/2

now, 1/5 = 20% , while 1/2 = 50%.

Therefore her probability of getting the correct answer improves by 30% [ not much in a REAL test though :P ]

5 0

3 years ago

I need to help with that

Bingel [31]

The ratio of people that can be served to milligrams of baking soda needed is:

Serving : Baking Soda
2 : 1600mg

Since you want 10 people, you can multiply this ratio by 5:5 to get

10 people served = 8000mg needed

8000mg = 8 grams

3 0

4 years ago

One technique of killing cancer cells involves inserting microscopic synthetic rods, called carbon nanotubules, into the cell. W

Vlad [161]

Answer:

The probability that the cell will be killed is 0.9328.

Step-by-step explanation:

We are given that five nanotubules are inserted in a single cancer cell. Independently of each other, they become exposed to near-infrared light with probabilities 0.2, 0.4, 0.3, 0.6, and 0.5.

Let the event that a cell is killed be 'A' and the event where the ith nanotubule kill the cell be ' $\text{B}_i$ '.

This means that the cell will get killed if $\text{B}_1 \bigcup \text{B}_2 \bigcup \text{B}_3 \bigcup \text{B}_4 \bigcup \text{B}_5$ happens. This represents that the cell is killed if nanotubule 1 kills the cell, or nanotubule 2 kills the cell, and so on.