Answer:
![20\:\mathrm{miles}](https://tex.z-dn.net/?f=20%5C%3A%5Cmathrm%7Bmiles%7D)
Step-by-step explanation:
After travelling two hours, the two cruise ships form a triangle. One of the legs of this triangle will be the distance Cruise A travelled, and another will be the distance Cruise B travelled. We can find the distance they travel using:
![s=\frac{d}{t}, d=s\cdot t](https://tex.z-dn.net/?f=s%3D%5Cfrac%7Bd%7D%7Bt%7D%2C%20d%3Ds%5Ccdot%20t)
Cruise A is travelling at 18 miles per hour for 2 hours. Therefore, Cruise A has travelled:
![d=s\cdot t=18\cdot 2=36\:\mathrm{miles}](https://tex.z-dn.net/?f=d%3Ds%5Ccdot%20t%3D18%5Ccdot%202%3D36%5C%3A%5Cmathrm%7Bmiles%7D)
Cruise B is travelling at 15 miles per hour for 2 hours. Therefore, Cruise B has travelled:
![d=s\cdot t=15\cdot 2=30\:\mathrm{miles}](https://tex.z-dn.net/?f=d%3Ds%5Ccdot%20t%3D15%5Ccdot%202%3D30%5C%3A%5Cmathrm%7Bmiles%7D)
Because we are given the angle between these legs, we can use the Law of Cosines to find the third leg. The Law of Cosines is given by:
, where
,
, and
are interchangeable. Let
represent the distance between the two cruises. We have:
(one significant figure).
For the first problem it would take about 2500 revolutions to gover such a distance and in 500 revolutions, it will travel 1539.4 meters.
Answer:
44 cm
Step-by-step explanation:
So, it is asking what the bigger piece of the 60 cm board is. First you can divide it into two even pieces. That makes each piece 30 cm. but, it wants one of the two 14 cm bigger, right? So, now your going to add 14 cm to 30 cm, giving you 44 cm. But, if you do that then you will have to subtract 14 cm from the other board. That leaves you with the bigger board is 44 cm, and the smaller one is 16 cm.
Answer:
![n_{i+1} = -5n_i - 1](https://tex.z-dn.net/?f=n_%7Bi%2B1%7D%20%3D%20-5n_i%20-%201)
Step-by-step explanation:
-5*2 - 1 = -11
-5*-11 - 1 = 54
The answer is 11/2 hope this helps