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koban [17]
2 years ago
11

Select the correct answer. What happens when an electron absorbs energy? A. The electron moves from a lower energy orbital to a

higher energy orbital. B. The electron falls into the nucleus. C. The electron moves from a higher energy orbital to a lower energy orbital. D. The electron loses its charge.
Chemistry
1 answer:
umka2103 [35]2 years ago
3 0
I choose the option A.
The electron absorbs energy from specific wavelength then moving from a lower energy orbital to a higher energy orbital.
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a student determined that it requires 106220 j of energy to vaporize 47g of water. is the student is right​
shusha [124]
<h2>Answer:</h2>

He is right that the energy of vaporization of 47 g of water s 106222 j.

<h3>Explanation:</h3>

Enthalpy of vaporization or heat of vaporization is the amount of energy which is used to transform one mole of liquid into gas.

In case of water it is 40.65 KJ/mol. And 18 g of water is equal to one mole.

It means for vaporizing 18 g, 40.65 kJ energy is needed.

So for energy 47 g of water = 47/18 * 40.65 = 106.1 KJ

Hence the student is right about the energy of vaporization of 47 g of water.

7 0
3 years ago
A
BARSIC [14]

The number of C atoms in 0.524 moles of C is 3.15 atoms.

The number of SO_2 molecules in 9.87 moles  SO_2 is 59.43 molecules.

The moles of Fe in 1.40 x 10^{22} atoms of Fe is 0.23 x 10^{-1}

The moles of C_2H_6O in 2.30x10^{24} molecules of C_2H_6O is 3.81.

<h3>What are moles?</h3>

A mole is defined as 6.02214076 × 10^{23} of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

A. The number of C atoms in 0.524 mole of C:

6.02214076 × 10^{23} x 0.524 mole

3.155601758 atoms =3.155 atoms

B. The number of SO_2 molecules in 9.87 moles of SO_2:

6.02214076 × 10^{23} x 9.87

59.4385293 molecules= 59.43 molecules

C. The moles of Fe in 1.40 x 10^{22} atoms of Fe:

1.40 x 10^{22} ÷ 6.02214076 × 10^{23}

0.2324754694 x 10^{-1} moles.

0.23 x 10^{-1} moles.

D. The moles of C_2H_6O in 2.30x10^{24} molecules of C_2H_6O:

2.30x10^{24} ÷ 6.02214076 × 10^{23}

3.819239854 moles=3.81 moles

Learn more about moles here:

brainly.com/question/8455949

#SPJ1

6 0
1 year ago
What effect does light have on plant growth?
Varvara68 [4.7K]

Explanation:

Light intensity influences the manufacture of plant food, stem length, leaf color and flowering. Generally speaking, plants grown in low light tend to be spindly with light green leaves. A similar plant grown in very bright light tends to be shorter, better branches, and have larger, dark green leaves.

3 0
2 years ago
Given the information you now know, what is the effect of hyperventilation on blood pH?pH? During hyperventilation, the rapid in
Ksju [112]

Answer:

When hypercapnia processes occur, where the concentration of carbon dioxide gas increases in the blood, the protonization of the blood increases, this means that the H + ions increase in concentration, thus generating metabolic acidosis.

This metabolic acidosis is regulated by various systems, but the respiratory system collaborates by generating hyperventilation, to increase blood oxygen pressures, decrease CO2 emissions, and indirectly decrease acidity.

Explanation:

This method of regulating the body is crucial, since the proteins in our body will not be altered if they do not happen.

The enzymes, the red globules, and many more fundamental things for life ARE PROTEINS, that in front of acidic media these modify their structure by denaturing themselves and ceasing to fulfill their functions. This is the reason why it seeks to neutralize the blood pH when it comes to an increase in CO2.

3 0
3 years ago
Can anyone help me with this since it is a quiz and I am really bad at chemistry!!
lord [1]

Answer:

Down below <3

Explanation:

1. <u> 1 </u> N_{2} + <u> 3 </u> H_{2} ---> <u> 2 </u> NH_{3}

2. <u> 2 </u> KClO_{3} ---> <u> 2 </u> KCl + <u> 3 </u> O_{2}

3. <u> 1 </u> Na_{3}PO_{4} + <u> 3 </u> HCl ---> <u>_ 3_</u> NaCl + <u> 1 </u> H_{3}PO_{4}

4. <u> 1 </u> C_{2}H_{6}O + <u> 3 </u> O_{2} ---> <u> 2 </u> CO_{2} + <u> 3 </u> H_{2}O

5 0
3 years ago
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